Page 155 - Fundamentals of Enhanced Oil and Gas Recovery
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143
             Thermal Recovery Processes


                                                           ð N    1  1
                                       dq 5 dq 2 dq r 5 kgsinθ   2      dξ                (5.5)
                                                            0   ν   ν R
                      The other possibility is to have integral limit up to ξ max , beyond which no
                   drainage is practically happening.
                                                     m

                                       ν s  5  T2T R                                      (5.6)
                                       ν     T s 2T R    m 5 3 2 4ðtypicallyÞ
                                             ð N
                                                  1    1       α 1
                                                  ν  2    dξ 5                            (5.7)
                                              0       ν R      U mν s
                                                       Kgαsinθ
                                                   q 5                                    (5.8)
                                                        mν s U


                   5.2.1.1 SAGD-Material Balance
                   The flow into an incremental element is less than that leaving the element; the
                   difference determines the rate of interface advancement.

                                                           dy
                                                dq 5 φΔS o      dx                        (5.9)
                                                 t
                                                           dt
                                                               x
                                                 dq           dy

                                                     5 φΔS o                             (5.10)
                                                 dx           dt
                                                    t            x

                    dy=dt  interface velocity U and inclination angle θ.
                         x
                      Determining interface velocity in SAGD:

                                                            dy
                                                 U 52cosθ                                (5.11)
                                                            dt
                                                                x

                                                     dy
                                                          , 0                            (5.12)
                                                      dt
                                                         x
                                                           dy
                                                    tanθ 5                               (5.13)
                                                           dx
                      SAGD-interface advancement velocity is calculated as
                                                       Kgαsinθ
                                                   q 5                                   (5.14)
                                                        mν s U
                                                        Kgαsinθ
                                                q 52                                     (5.15)
                                                      mν s cosθ  @y
                                                               @t
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