Page 366 - Handbook Of Multiphase Flow Assurance
P. 366

Computer code (Makogon, 1994, 1997)              365

                       npass1:=pass[bonds[j]];
                       end;
                  if npass1<>npass2 then short:=true;
                  end;
                  if short then
                  begin
                  Conti;
                                          {if no branches left go to next link}
                  if (not contin)or(nr=1) then goto 2;
                  Conti2;
                  goto 1;                        {see if this is a new ring}
                  end;
                  for j:=1 to nr−1 do            {between positions j and k of ring}
                   begin                        {where k>j, shorted by one bond}
                   if j=1 then
                     m1:=nr−1
                   else
                     m1:=nr;
                   for k:=j+2 to m1 do
                     if (order[rin[k]] >2) and (order[rin[j]] >2) then
                     begin
                     for m2:=1 to n do          {seek one-bond short circuits}
                       if ((nhb[m2,1]=rin[j])and(nhb[m2,2]=rin[k])) or
                          ((nhb[m2,2]=rin[j])and(nhb[m2,1]=rin[k])) then
                         begin
                         short:=true;
                         Conti;
                                                 {no branches left goto next link}
                         if (not contin)or(nr=1) then goto 2;
                         Conti2;
                         goto 1;                 {see if this is a new ring}
                         end;
                     end;
                   end;
                  for j:=1 to nr−1 do            {between positions j and k of ring}
                   begin                        {where k>j}
                   if j=1 then
                     m1:=nr−1
                   else
                     m1:=nr;
                   for k:=j+2 to m1 do
                     if (order[rin[k]] >2) and (order[rin[j]] >2) then
                     begin
                     if (k−j)<(nr/2)then
                       dist:=k−j
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