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all sorted out

Here is the existing program. You were to add in the missing code
that sorts the data, highest-to-lowest.

scores = []
result_f = open("results.txt")
for line in result_f:
(name, score) = line.split()
scores.append(float(score))
result_f.close() At this point in the code, the array is
in memory but it's not in the order you
need. It's unsorted.
scores.sort()
scores.reverse() These two method calls will sort
the data into the required order.

print("The top scores were:")
print(scores[0])
Now that the array is sorted, the first
print(scores[1])
three elements contain the high scores.
print(scores[2])

After the call to sort() and
reverse(), the array is sorted
in the order you need.

boxes

0 1 2 3

Geek Bits

It was very simple to sort an array of data using just two lines of code. But it turns out you can do even
better than that if you use an option with the sort() method. Instead of using these two lines:
scores.sort()
scores.reverse()
you could have used just one, which gives the same result: scores.sort(reverse = True)

140 Chapter 4