Page 239 - How To Solve Word Problems In Calculus
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We reject the negative solution.Since the profit function is
                                   continuous on the closed interval [0, 30], we compare the value of
                                   P (x)at x = 20 with its values at the interval endpoints.

                                            P (0) =−40    P (20) = 920    P (30) = 380
                                   The maximum profit occurs when 20 cameras are sold daily.
                              10. This is an inventory problem.We let x represent the size of each
                                   printing in units of 1000 books.The storage (holding) cost is

                                                                                x
                                              H(x) = (annual storage cost per item)
                                                                                2

                                                          x
                                                  = 600
                                                          2
                                                  = 300x
                                   The ordering cost is
                                            O(x) = (cost per printing)(number of printings)

                                                                    q
                                                 = (cost per printing)
                                                                    x
                                                                         Remember, q is in thousands.
                                                          200
                                                 = (3750)
                                                           x
                                                 = 750,000x −1
                                   The total printing cost, $3 × 200,000 = $600,000 can be ignored
                                   (see note on page 218).
                                                      C (x) = H(x) + O(x)
                                                          = 300x + 750,000x −1

                                                     C (x) = 300 − 750,000x −2
                                                                   750,000
                                                         0 = 300 −
                                                                     x 2
                                                   750,000
                                                          = 300
                                                     x 2
                                                         2
                                                     300x = 750,000
                                                         2
                                                        x = 2500
                                                         x = 50
                                   To minimize cost, each printing should be 50,000 copies.

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