Page 67 - How To Solve Word Problems In Calculus
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Step4
                                                        dx      dy
                                                     2x    + 2y    = 0
                                                        dt      dt

                                                         dx     dy
                                                       x    + y    = 0
                                                         dt     dt



                                   Step5
                                            dy
                                   3 · 2 + 4   = 0       Since dx/dt is positive and the point is in the
                                            dt           first quadrant, the point is moving along the
                                                         circle in a clockwise direction. It makes sense
                                    dy     3             that dy/dt is negative, as the point is moving
                                       =−    cm/sec      down.
                                    dt     2


                               EXAMPLE 8

                               The dimensions of a rectangle are continuously changing. The
                               width increases at the rate of 3 in/sec while the length de-
                               creases at the rate of 2 in/sec. At one instant the rectangle is a
                               20-inch square. How fast is its area changing 3 seconds later?
                               Is the area increasing or decreasing?

                                   Solution
                                   Step1
                                   Represent the width and length of the rectangle by x and
                               y, respectively.
                                                              x





                                                        y






                                   Step2
                                           dx      dy                 dA
                                   Given:     = 3,    =−2       Find:      3 seconds later
                                           dt      dt                  dt
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