Page 196 - Intro to Tensor Calculus
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191



               Work and Potential Energy

                   Define M as the constant mass of the particle as it moves along the curve defined by equation (2.2.1).
                        r
               Also let Q denote the components of a force vector (in appropriate units of measurements) which acts upon
               the particle. Newton’s second law of motion can then be expressed in the form

                                                 r
                                                Q = Mf  r    or    Q r = Mf r .                       (2.2.18)

                                                                                                r
                                                                                           r
                   The work done W in moving a particle from a point P 0 to a point P 1 along a curve x = x (t),r =1, 2, 3,
               with parameter t, is represented by a summation of the tangential components of the forces acting along the
               path and is defined as the line integral

                                      Z  P 1  dx r   Z  P 1       Z  t 1  dx r   Z  t 1
                                                               r
                                                                                        r
                                 W =      Q r    ds =     Q r dx =    Q r   dt =    Q r v dt          (2.2.19)
                                              ds                         dt
                                       P 0             P 0         t 0            t 0
                              s
               where Q r = g rsQ is the covariant form of the force vector, t is the time parameter and s is arc length along
               the curve.
               Conservative Systems
                   If the force vector is conservative it means that the force is derivable from a scalar potential function

                                                                           ∂V
                                    2
                                 1
                                          N
                         V = V (x ,x ,...,x )    such that   Q r = −V ,r = −  ,  r =1,... ,N.         (2.2.20)
                                                                           ∂x r
               In this case the equation (2.2.19) can be integrated and we find that to within an additive constant we will
               have V = −W. The potential function V is called the potential energy of the particle and the work done
               becomes the change in potential energy between the starting and end points and is independent of the path
               connecting the points.

               Lagrange’s Equations of Motion


                   The kinetic energy T of the particle is defined as one half the mass times the velocity squared and can
               be expressed in any of the forms
                                                  2
                                        1     ds     1    2   1             1
                                                                     m n
                                                                                    m n
                                    T =   M        =   Mv =    Mg mnv v =    Mg mn ˙x ˙x ,            (2.2.21)
                                        2     dt     2        2             2
               where the dot notation denotes differentiation with respect to time. It is an easy exercise to calculate the
               derivatives
                                                   ∂T           m
                                                       = Mg rm ˙x
                                                   ∂ ˙x r

                                                d  ∂T              m   ∂g rm  n m
                                                         = M g rm ¨x +      ˙ x ˙x                    (2.2.22)
                                               dt  ∂ ˙x r              ∂x n
                                                   ∂T    1   ∂g mn  m n
                                                       =   M      ˙ x ˙x ,
                                                   ∂x r  2    ∂x r
               and thereby verify the relation

                                          d   ∂T      ∂T
                                                   −     = Mf r = Q r ,  r =1,... ,N.                 (2.2.23)
                                          dt  ∂ ˙x r  ∂x r
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