Page 302 - Introduction to Continuum Mechanics
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286 Pure Bending of a Curved Beam
Fig. 5.17
In the following we shall show that the state of stresses given in Eqs. (5.17.10) together with
T zz = 0 can be used to give the desired solution. The stress components are:
Since the surfaces r = a and r = b are traction-free, the constants yl, B and C must satisfy
On the face 0 = a, there is a distribution of normal stress TQQ given by Eq. (5.19.1b ). Let us
compute the resultant of this distribution of the normal stresses:
In view of Eqs. (5.19.2), we have
