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Part B Sum of Tensors 17








         or


           We can concisely derive Eq. (2B3.1a) using indicial notation as follows: From a = a/Cj, we
         get Ta = Tfl/e,- = a/Te/. Since Te, = 7)/ey, (Eq. (2B2.1b)), therefore,



         i.e.,


           Eq. (2B3.1d) is nothing but Eq. (2B3.1a) in indicial notation. We see that for the tensorial
         equation b = Ta, there corresponds a matrix equation of exactly the same form, i.e., [b] = [T][a].
         This is the reason we adopted the convention that Tej = T^i+7*2162+ 73163, etc. If we had
                                            t
                                                    e
         adopted the convention Te^ = 7ne 1+7 1262+^I3 3'  etc -'  tnen we  would have obtained
               7*
         [b]=[T] [a] for the tensorial equation b = Ta, which would not be as natural.
                                          Example 2B3.1
           Given that a tensor T which transforms the base vectors as follows:

                                        Tej = 2e 1-6e 2+4e 3
                                        T02 = 3ej+462-63
                                        Te 3 = -26J+62+263
         How does this tensor transform the vector a = ej+262+363?
           Solution. Using Eq. (2B3.1b)
                                   b
                                    i\ [2 3 -2] fll [2"
                                   b 2 = -6     4 1 2 = 5
                                         [ 4 -1     2J [3J   [8
                                   b 3
         or
                                         b = 2e 1+5e 2+8e 3

         2B4 Sum of Tensors
           Let T and S be two tensors and a be an arbitrary vector. The sum of T and S, denoted by
         T + S, is defined by:
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