Page 307 - Introduction to Naval Architecture
P. 307

292                VIBRATION, NOISE AND SHOCK

          In the calculation the mass per unit length must allow for the mass of
        the entrained water using one of the methods described for dealing
        with added virtual mass. The bending theory used ignores shear
        deflection and rotary inertia effects. Corrections for these are made at
        the end by applying factors, based on r s and r r, to the calculated
        frequency as discussed earlier,
        The energy method
        This method uses the principle that, in the absence of damping, the
        total energy of a vibrating system is constant. Damping exists in any real
        system but for ships it is acceptable to ignore it for the present purpose.
        Hence the sum of the kinetic and potential energies is constant.
          In a vibrating beam the kinetic energy is that of the moving masses
        and initially this is assumed to be due to linear motion only. Assuming
        simple harmonic motion and a mass distribution, the kinetic energy is
        obtained from the accelerations deduced from an assumed deflection
        profile and frequency. The potential energy is the strain energy of
        bending,
          When the beam is passing through its equilibrium position the
        velocity will be a maximum and there will be no bending moment at
        that instant. All the energy is kinetic. Similarly when at its maximum
        deflection the energy is entirely potential. Since the total energy is
        constant the kinetic energy in the one case can be equated to the
        potential energy in the other.
          As in the deflection method the initial deflection profile is taken as
        that of a uniform bar. As before allowance is made for shear deflection
        and for rotary inertia. Applying this energy method to the case of the
        simply supported, uniform section, beam with a concentrated mass M
        at mid-span and assuming a sinusoidal deflection curve, yields a
        frequency of:
                 4
            1 fn EI\°- 5                I /48£/\°- 5
           ___ - _        compared with — - for the exact solution.
                             F
                4
        Since 7T /2 is 48.7 the two results are in good agreementThis simple
        example suggests that as long as the correct end conditions are satisfied
        there is considerable latitude in the choice of the form of the deflection
        profile.

        Calculation of higher modes
        It might be expected that the frequencies of higher modes could be
        obtained by the above methods by assuming the appropriate deflection
        profile to match the mode needed. Unfortunately, instead of the
        assumed deflection curve converging to the correct one it tends to
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