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220  Chapter 8: Catalysis and Catalytic Reactions

                                    Consider two cases: (i) the product is strongly adsorbed and inhibits the reaction; and (ii)
                                    it is very weakly adsorbed.
                                 (b) The decomposition of acetaldehyde on Pt at temperatures between 960 and  12OO”C,  and
                                    at pressures between 3.33 and 40.0  kPa,  appears to be a bimolecular reaction with no
                                    inhibition by reaction products.
                                 (c) A study of the kinetics of ethanol dehydrogenation over Cu in the presence of water vapor,
                                    acetone, or benzene showed that any one of these three inhibited the reaction.
                                 (d) In the reaction of nitrous oxide  (NzO)  with hydrogen over Pt (SOi’-580°C  pnZ  = 7 to 53
                                    kPa,   pQo  = 40 to 53  kPa),  it has been observed that NzO  is weakly adsorbed and  HZ  is
                                    very  strongly  adsorbed.
                             8-6 For the surface-catalyzed gas-phase reaction A(g) + B(g)  -+  products, what is the form of
                                 the rate law, according to the LH model, if A is strongly adsorbed and B is weakly adsorbed?
                                 Assume there is no adsorption of product(s). Interpret the results beyond what is already spec-
                                 ified.
                             8-7 For the reaction in problem 8-6, suppose there is one product P which can be adsorbed. Derive
                                 the form of the rate law according to the LH model, if
                                 (a) A, B, and P are all moderately adsorbed;
                                 (b) A and B are weakly adsorbed and P is strongly adsorbed. (Interpret the result further.)
                             8-8 Consider the reaction mechanism for methanol synthesis proposed in Figure 8.3:

                                                     CO.s+H.s  -+  HCO.s+s                          (1)
                                                    HCO.s+H.s  --z  H$ZO.s+s                        (2)
                                                    H2C0.s  +H.s + HaC0.s +  s                      (3)
                                                   HsCO.s+H.s   -+ HsCOH.s+s                        (4)


                                 Assume that the coverages of H, CO, and methanol are given by the  Langmuir  adsorption
                                 isotherm in which CO,  Hz,  and methanol adsorption compete for the same sites, and the in-
                                 termediates  H,CO@s  are present in negligible quantities.
                                 (a) Assume that step (1) is rate limiting, and write the general rate expression.
                                 (b) Assume that (3) is rate limiting (steps (1) and (2) are in equilibrium), and write the general
                                    rate  expression.
                                 (c) Experimental data are represented by =  kpC$5di;

                 v
                                                          rCH,OH
              “OP
             0                   (d) How would the rate law change if the  H,CO*s  intermediates were allowed to cover a
                                    To obtain this rate law, which of the surface steps above is rate limiting?
                                    substantial fraction of sites? (This can be attempted analytically, or you may resort to
                                    simulations.)
                              8-9 (a) Rate laws for the decomposition of PHa (A) on the surface of MO (as catalyst) in the
                                    temperature range 843-9 18 K are as follows:

                                                 pressure,  p&Pa      rate law
                                                     +O         (-IA)  =  +A
                                                    8 x 1O-3    (-rA) = kPd@  + bpA)
                                                   2.6 x 1O-2   (-rA)  =  constaut

                                    Interpret these results in terms of a Langmuir-Hinshelwood mechanism.
                                 (b) In the decomposition of N20 on Pt, if NzO  is weakly adsorbed and 02 is moderately
                                     adsorbed, what form of rate law would be expected based on a Langmuir-Hinshelwood
                                     mechanism?  Explain  briefly.
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