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Chapter 6. Inner-Product Spaces
                       106
                                                                                  u
                                                                                     u + v
                                                                        u − v
                                                           v                                 v
                                                                         u
                                                                 The parallelogram equality
                                              6.14  Parallelogram Equality: If u, v ∈ V, then

                                                                                              2
                                                                              2
                                                                                       2
                                                                   2
                                                            u + v  + u − v  = 2( u  + v  ).
                                                Proof: Let u, v ∈ V. Then
                                                           2          2
                                                    u + v  + u − v  = u + v, u + v + u − v, u − v
                                                                             2      2
                                                                       = u  + v  + u, v + v, u
                                                                                2      2
                                                                           + u  + v  −Pu, v −Pv, u
                                                                               2
                                                                                      2
                                                                       = 2( u  + v  ),
                                              as desired.
                                              Orthonormal Bases


                                                A list of vectors is called orthonormal if the vectors in it are pair-
                                              wise orthogonal and each vector has norm 1. In other words, a list
                                              (e 1 ,...,e m ) of vectors in V is orthonormal if  e j ,e k   equals 0 when
                                              j  = k and equals 1 when j = k (for j, k = 1,...,m). For example, the
                                                               n
                                              standard basis in F is orthonormal. Orthonormal lists are particularly
                                              easy to work with, as illustrated by the next proposition.

                                              6.15  Proposition:  If (e 1 ,...,e m ) is an orthonormal list of vectors
                                              in V, then
                                                                             2      2            2
                                                          a 1 e 1 + ··· + a m e m   =|a 1 | + ··· + |a m |
                                              for all a 1 ,...,a m ∈ F.

                                                Proof:   Because each e j has norm 1, this follows easily from re-
                                              peated applications of the Pythagorean theorem (6.3).

                                                Now we have the following easy but important corollary.
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