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Chapter 7. Operators on Inner-Product Spaces
                       138
                                              Normal Operators on Real
                                              Inner-Product Spaces
                                                The complex spectral theorem (7.9) gives a complete description
                                              of normal operators on complex inner-product spaces. In this section
                                              we will give a complete description of normal operators on real inner-
                                              product spaces. Along the way, we will encounter a proposition (7.18)
                                              and a technique (block diagonal matrices) that are useful for both real
                                              and complex inner-product spaces.
                                                We begin with a description of the operators on a two-dimensional
                                              real inner-product space that are normal but not self-adjoint.

                                              7.15  Lemma:    Suppose V is a two-dimensional real inner-product
                                              space and T ∈L(V). Then the following are equivalent:

                                              (a)  T is normal but not self-adjoint;
                                              (b)  the matrix of T with respect to every orthonormal basis of V
                                                   has the form
                                                                             a  −b
                                                                             b   a    ,
                                                   with b  = 0;
                                              (c)  the matrix of T with respect to some orthonormal basis of V has
                                                   the form

                                                                             a  −b
                                                                                      ,
                                                                             b   a
                                                   with b> 0.


                                                Proof:   First suppose that (a) holds, so that T is normal but not
                                              self-adjoint. Let (e 1 ,e 2 ) be an orthonormal basis of V. Suppose

                                                                                   a  c
                                              7.16               M T, (e 1 ,e 2 ) =       .
                                                                                   b  d
                                                                                        2
                                                                                    2
                                                        2
                                                                  2
                                                              2
                                                                               2
                                              Then  Te 1   = a + b and  T e 1   = a + c . Because T is normal,
                                                                          ∗
                                                                                                             2
                                                                                                       2
                                               Te 1  = T e 1   (see 7.6); thus these equations imply that b = c .
                                                         ∗
                                              Thus c = b or c =−b. But c  = b because otherwise T would be self-
                                              adjoint, as can be seen from the matrix in 7.16. Hence c =−b,so

                                                                                  a  −b

                                              7.17              M T, (e 1 ,e 2 ) =         .
                                                                                  b   d
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