Page 240 - Linear Algebra Done Right
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                                             Determinant of a Matrix
                         Our goal is to prove that det T = det M(T) for every T ∈L(V) and
                      every basis of V. To do this, we will need to develop some proper-
                                                                                          be devoted just to
                                                                                          deriving properties of
                      ties of determinants of matrices. The lemma below is the first of the  An entire book could
                      properties we will need.                                            determinants.
                                                                                          Fortunately we need
                      10.28   Lemma:    Suppose A is a square matrix. If B is the matrix  only a few of the basic
                      obtained from A by interchanging two columns, then                  properties.
                                                det A =− det B.
                         Proof: Suppose A is given by 10.24 and B is obtained from A by
                      interchanging two columns. Think of the sum 10.25 defining det A and
                      the corresponding sum defining det B. The same products of a’s appear
                      in both sums, though they correspond to different permutations. The
                      permutation corresponding to a given product of a’s when computing
                      det B is obtained by interchanging two entries in the corresponding
                      permutation when computing det A, thus multiplying the sign of the
                      permutation by −1 (see 10.23). Hence det A =− det B.

                         If T ∈L(V) and the matrix of T (with respect to some basis) has two
                      equal columns, then T is not injective and hence det T = 0. Though
                      this comment makes the next lemma plausible, it cannot be used in the
                      proof because we do not yet know that det T = det M(T).

                      10.29   Lemma: If A is a square matrix that has two equal columns,
                      then det A = 0.

                         Proof: Suppose A is a square matrix that has two equal columns.
                      Interchanging the two equal columns of A gives the original matrix A.
                      Thus from 10.28 (with B = A), we have det A =− det A, which implies
                      that det A = 0.
                         This section is long, so let’s pause for a paragraph. The symbols✽

                      that appear on the first page of each chapter are decorations intended
                      to take up space so that the first section of the chapter can start on the
                      next page. Chapter 1 has one of these symbols, Chapter 2 has two of
                      them, and so on. The symbols get smaller with each chapter. What you
                      may not have noticed is that the sum of the areas of the symbols at the
                      beginning of each chapter is the same for all chapters. For example, the
                                                                                   √
                      diameter of each symbol at the beginning of Chapter 10 equals 1/ 10
                      times the diameter of the symbol in Chapter 1.
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