Page 252 - Linear Algebra Done Right
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                                                      −r sin θ
                                               cos θ
                                                                ,
                                               sin θ
                                                       r cos θ
                      as you should verify. The determinant of the matrix above equals r,                  243
                      thus explaining why a factor of r is needed when computing an integral
                      in polar coordinates.
                         Finally, when n = 3, we can use the change of variables induced by
                      spherical coordinates. In this case σ is defined by
                                σ(ρ, ϕ, θ) = (ρ sin ϕ cos θ, ρ sin ϕ sin θ, ρ cos ϕ),
                      where we have used ρ, θ, ϕ as the coordinates instead of x 1 ,x 2 ,x 3
                      for reasons that will be obvious to everyone familiar with spherical
                      coordinates (and will be a mystery to everyone else). For this choice
                      of σ, the matrix of partial derivatives corresponding to 10.39 is
                                                                         
                                   sin ϕ cos θ  ρ cos ϕ cos θ  −ρ sin ϕ sin θ
                                                                         
                                  sin ϕ sin θ  ρ cos ϕ sin θ  ρ sin ϕ cos θ  ,
                                      cos ϕ      −ρ sin ϕ          0

                      as you should verify. You should also verify that the determinant of the
                                                                                 2
                                           2
                      matrix above equals ρ sin ϕ, thus explaining why a factor of ρ sin ϕ
                      is needed when computing an integral in spherical coordinates.
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