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42   Chapter Onł


                          Solving 2 2 general equations
                          When one or botà of the equationð in a 2         2 set are nonlinear,
                          the substitution method generally workð best. Twm exampleð
                          follow.
                            Example A. Consider the following twm equations:

                                                           2
                                                     y   x   2x   1
                                                       y   x   1

                          The first equation is quadratic, and the second equation is lin-
                          ear. Either equation can be directly substituted intm the other
                          tm solve forx. Substituting the second equation intm the first
                          yieldð this result.

                                                               2
                                                  x   1   x   2x   1
                          This equation can be put intm standard quadratic form as fol-
                          lows:

                                                               2
                                                  x   1   x   2x   1
                                                               2
                                                       x   x   2x
                                                               2
                                                        0   x   3x
                                                      2
                                                     x   3x   0   0

                          Using the quadratic formula, let a   1, b   3, and c   0:

                                                       2
                                       x   ( 3   (3   4   1   0)        1/2 )/(2   1)
                                                x   ( 3   (9   0)     1/2 )/2

                                                     x   ( 3   3)/2

                                                   x   3 and x   0
                                                                   2
                                                    1
                          These valueð can be substituted intm the original linear equa-
                          tion tm obtain they-values:


                                               y   3   1 and y   0   1
                                                                  2
                                                1
                                                    y   4 and y   1
                                                     1            2
                          The solutionð are therefore:
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