Page 66 - Matrices theory and applications
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49
                                                3.3. Normal and Symmetric Real-Valued Matrices
                              us denote by B = {v 1 ,... ,v n } an orthonormal eigenbasis (Mv j = λ j v j ).
                                     n
                              If x ∈ IR , let us denote by y 1 ,... ,y n the coordinates of x in the basis B.
                                                                                    n
                              Finally, let us denote by  ·   2 the usual Euclidean norm on IR .Then


                                                                              2
                                             T
                                                                     2
                                                           2
                                            x Mx =
                                                                    y = λ n  x  .
                                                        λ j y ≤ λ n
                                                                              2
                                                           j
                                                                     j
                                                                  j
                                                      j
                                                   2
                                    T
                              Since v Mv n = λ n  v n   , we deduce the value of the largest eigenvalue of
                                    n
                                                   2
                              M:
                                                     T
                                                   x Mx            T       2
                                          λ n =max     2  =max x Mx | x  =1 .             (3.1)
                                                                           2
                                                x =0  x
                                                       2
                              Similarly, the smallest eigenvalue of a real symmetric matrix is given by
                                                     T
                                                    x Mx          T        2
                                           λ 1 =min     2  =min{x Mx | x  =1}.            (3.2)
                                                                           2
                                                x =0  x
                                                        2
                              For a Hermitian matrix, the formulas (3.1,3.2) remain valid when we replace
                               T
                              x by x .
                                     ∗
                                We evaluate the other eigenvalues of M ∈ Sym (IR) in the following
                                                                           n
                                                               n
                              way. For every linear subspace F of IR of dimension k, let us define
                                                    T
                                                   x Mx            T             2
                                     R(F)= max           =max x Mx | x ∈ F,  x  =1 .
                                                                                 2
                                            x∈F \{0}  x  2
                                                       2
                              The intersection of F with the linear subspace spanned by {v k ,... ,v n } is
                              of dimension greater than or equal to one. There exists, therefore, a nonzero
                              vector x ∈ F such that y 1 = ··· = y k−1 = 0. One has then
                                                      n
                                                                              2
                                                                     2
                                              T
                                            x Mx =         2        y = λ k  x  .
                                                        λ j y ≥ λ k
                                                           j         j        2
                                                     j=k          j
                              Hence, R(F) ≥ λ k .Furthermore, if G is the space spanned by {v 1 ,... ,v k },
                              one has R(G)= λ k .Thus, we have
                                                 λ k =min{R(F) | dim F = k}.
                              Finally, we may state the following theorem.
                              Theorem 3.3.2 Let M be an n × n real symmetric matrix and λ 1 ,... ,λ n
                              its eigenvalues arranged in increasing order, counted with multiplicity. Then
                                                                     T
                                                                    x Mx
                                                  λ k =  min  max       2  .
                                                      dim F =k x∈F \{0}  x
                                                                        2
                              If M is complex Hermitian, one has similarly
                                                                     ∗
                                                                    x Mx
                                                  λ k =  min   max      2  .
                                                       dim F =k x∈F \{0}  x
                                                                        2
                              This formula generalizes (3.1, 3.2).
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