Page 4 - Singiresu S. Rao-Mechanical Vibrations in SI Units, Global Edition-Pearson (2017)
P. 4

Equivalent Masses, Springs and Dampers
                Equivalent masses

                      m           M               Mass (M) attached at end of    m eq = M +  m
                                                  spring of mass m                        3




                                  M               Cantilever beam of mass m               33
                           m                      carrying an end mass M        m eq = M +  140  m





                         M                        Simply supported beam of      m eq = M + 0.5 m
                                                  mass m carrying a mass
                   m                              M at the middle




                                                  Coupled translational and               J 0
                                                  rotational masses             m eq = m +  2
                       J 0                                                               R
                                                                                           2
                                         R                                      J eq = J 0 + mR
                m

                      m 1    m 2     m 3          Masses on a hinged bar                    l 2  2   l 3  2
                                                                                m eq 1  = m 1 + a b m 2 + a b m 3
                                                                                            l 1      l 1
                    l 1
                       l 2
                           l 3

                Equivalent springs
                                                  Rod under axial load          k eq =  EA
                                                  1l = length,  A = cross sectional area2   l

                                                  Tapered rod under axial load  k eq =  pEDd
                                                  1D, d = end diameters2              4l

                                                  Helical spring under axial load    Gd 4
                                                  (d = wire diameter,           k eq =  8nD 3
                                                  D = mean coil diameter,
                                                  n = number of active turns)

                                                  Fixed-fixed beam with              192EI
                                                  load at the middle            k eq =  l 3
   1   2   3   4   5   6   7   8   9