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System design aids  22 1


           4.3.4 Problem in electrodialysis: energy demand
           A  light  brackish  water  of  the specijication  below  requires  demineralisation  using  a
           500 cell pair, 7  x  0.75 rn  electrodialysis stack for potable  water production:  Na+,
           830 ppm; Cl-,  1530 ppm; Ca2", 100 ppm, S042 , 50 ppm; Mg2+, 60 ppni; HC03-,
           120 ppm.
             It is desired that the sodium content be halved. If the ED softens at twice the rate of
           desalination according to first order kinetics, and the process operates with an overall
           current eficiency of  95%  calculate (a) the total current required, and (b) the specific
           energy demand in kWh rnP3 for a conversion of  8.5% and an average production rate of
           500 rn3/day desalinated  water. How  would  the specific energy  demand  change if  a
           further stage were added to yielda 75% desalinatedproduct?
             Assume specific cell pair area resistance  is given by: r (ohms cm2) = IO + (1 04/
           C,,,,),  C,,,  being  the average concentration  in meq 1-'of  the diluate  stream passing
           through the stack.


           Solution
           Electrodialysis demands a knowledge of  the concentration of charge, since this
           can be directly related to the current demanded by the Faraday equation. Thus
           all concentrations must be converted to meq/l by dividing by the molar weight
           and multiplying by the charge:



                  --    mg/l        mdl                        mg/l         m  g
           Na'          830         36           CI            1530         43
           CaL+         100          5           so42            50          1
           Mg2+          60          5           HC03-          120          -
                                                                             7
           Total                    46                                      46
           -
             Since one unit of charge will shift a cation and an anion simultaneously, the
           calculation of the current is based on the total cations or anions removed and not
           the sum of both.
             If  hardness  (i.e. Ca2+ and Mg2+) is  removed  at twice  the rate  of  sodium
           according to first order kinetics, then:
               Rate of  removal = -kc  for first-order kinetics





           where C and Co are the outlet and inlet concentrations respectively and k is the
           first-order  rate  constant.  Thus,  the  residual/influent  hardness  is  (residual/
           influent salinity)2.
             The composition of the desalinated product in meq/l can then be calculated
           along with the amount of material removed (AC) and the average concentration
           of the diluate (Cave) respectively from the difference and average of the inlet and
           desalinated product streams:
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