Page 460 - Modelling in Transport Phenomena A Conceptual Approach
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440     CHAPTER IO.  UNSTEADY MICROSCOPIC BAL. WITHOUT GEN.

             where A and B are constants. Since the problem is symmetric around the z-axis,
             then 0, and hence G, must be even functions2 of E. Therefore, A = 0.  Application
             of  the boundary condition defined by Eq.  (10.222) gives
                                            BcosX = 0                        (10.225)

             For a nontrivial solution, the eigenvalues are given by

                     COSX=O      3      An=          T    n=0,1,2, ...       (10.2-26)

             Therefore, the general solution is

                                                                             (10.227)


             The unknown coefficients C, can be determined by  using the initial condition in
             Eq. (10.2-15). The result is
                                    1 = c c, cos [ (n + ;)  4                (10.2-28)
                                         00

                                        n=O
             Since the eigenfunctions are simply orthogonal, multiplication of  Eq.  (10.228) by
             cos [(m + i) 7r<]  and integration from < = 0 to < = 1 gives




                                                                             (10.2-29)
             Note that the integral on the right side of  Eq.  (10.2-29) is zero when n # m and
             nonzero when n = m.  Therefore, when n = m the summation drops out and Eq.
             (10.2-29) reduces to the form





             Evaluation of  the integrals gives

                                              sin [(n + +) 7r3
                                       Cn = 2                                (10.2-31)
                                                (n++)a
             Since sin (n + a) ?r = (-  l)", the solution becomes


                                                                             (10.232)


                2A function  f(s) is said  to  be an odd function  if  f(-s) = -f(z) and an  even function  if
             f(-z) = fb).
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