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B.1. FIRST-ORDER EQUATIONS WlTH EXACT SOLUTIONS                     535


           On the other hand,  the intensive properties  are homogeneous functions of  order
           zero and can be expressed as


                                                                           (B. 1- 15)



           Example B.3  Solve the following differential equation

                                    xydx-(x2+y2)dy=0
           Solution

           Since both of  the functions

                                       M  = xy
                                       N = - (x2 + y2)
           are homogeneous  of  degree 2, the tmnsformation

                                y=ux  and  dy=udx+xdu                          (3)
           reduces the equation to the form

                                     -+-   1+u2  du = 0                        (4)
                                      dx
                                      X     u3
          Integration  of Eq.  (4) gives

                                     xu=cexp(&)                                (5)

          where C is an integration constant.  Substitution  of  u = y/x into Eq.  (5) gives the
          solution as
                                               1  x
                                     Y = Cexp [- 2Y
                                                 (-)2]

          B.1.4  Linear Equations

          In order to solve an equation of  the form
                                     dY
                                     - + P(.)  Y  = &(x)                  (B. 1-16)
                                     dx
          the first step is to find out an integrating factor, p, which is defined by

                                                                          (B. 1- 17)
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