Page 223 - Numerical methods for chemical engineering
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Problems                                                            209





                   cnstant
                   diaeter  L  = 50 cm
                            3
                  D  = 100 cm
                   3
                                                       z 5  = 150 cm
                                                      z = 125 cm, meas. D(z ) = 85 cm
                   variae                             4             4
                   diaeter  L  = 100 cm             z = 100 cm, meas. D(z ) = 55 cm
                           2
                     D(z)                           3              3
                                                   z = 75 cm, meas. D(z ) = 40 cm
                                                   2
                                                                 2
                   cnstant                         z 1  = 50 cm
                   diaeter  L 1  = 50 cm
                  D  = 35 cm
                    1
                                                   z = 0 cm
                                                   0
                     cindrica ie  L  = 20 cm
                                   p
                      dia   D  = 1 cm.
                           p
                                 ie tet t atseric ressre
                  Figure 4.21 Tank of variable cross-sectional area.
                  4.A.2. Compute the value of the following definite integral using both dblquad and Monte
                  Carlo integration,
                                                 √
                                              2   x
                                            '  '
                                                              2
                                                          2
                                        I D =      [(x − 1) + y ]dydx               (4.248)
                                             1  0
                  4.A.3. Consider the 1-D motion of a point mass, connected to the origin by a harmonic
                  spring, that experiences a frictional drag force and a time-dependent external force. The
                  equation of motion is

                                            2
                                           d x           dx
                                         m     =−Kx − ζ     + F ext (t)             (4.249)
                                           dt  2         dt
                                                                   √
                  Let the mass be 1 kg, and let the harmonic frequency ω c =  K/m be 2π rad/s. Let the
                  external force be F ext (t) = (10 −2  N)sin (ωt), where ω is set at 0.01ω c , 0.1ω c , 0.5ω c , 0.9ω c
                  0.99ω c , and 0.999ω c . Plot x(t) for each of these cases when ζ = 0 and describe what
                  happens as ω → ω c . Repeat for non zero ζ, and describe how the behavior changes as ζ
                  increases.
                  4.B.1. Consider the axisymmetric tank shown in Figure 4.21. We want to estimate the time
                                                                            3
                  that it takes for the tank to drain if filled with water (density 1000 kg/m , viscosity 0.001
                  Pa s). Let h(t) be the height of water in the tank, h(0) = 2m.v p (t). The mean velocity in
                  the drain pipe and the volumetric flow rate out of the tank is
                                               π   2    π           dh
                                       υ out (t) =  D v p =  [D(h)]  2              (4.250)
                                                   p
                                                4       4          dt
                  To obtain v p , we use the engineering Bernoulli equation to relate the velocity and pressure
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