Page 164 - Open-Hole Log Analysis and Formation Evaluation

2) reserves oil-in-place p 1.3. factor is Recovery of 20 thickness logs, From QUESTION both units for used is a where C N - _ as expressed properties. the and factor is a B. factor, pieces XxX 10° 10 10 X 10° X 10° 43.56 10° 7.7579 X Use C = TABLE 8.1 150
A
the
I.
ry
HCPV
=
Muskat
in
deduced
of
calculated
number
CX
theoretical
RECOVERY
primary
it
of
METHODS
54.9[b
#8.1
from
(1949)
is
°
The
factor
data:
using
oil
expressed

The
(1
band A.
solution-gas-drive
Neither
means
ft,
is
is
=
function
MM
formation
expressed
in
BCF
a
the
the
logs.
or
and
studies
in
acres
acres
recovery
MMm?
areal
expressed
FACTORS
STB
constant
Table
(SG)
by
feet.
hectares
gas
in
hectares
reserves,
of the
=
=
=
b
useful.
of these
8.1

have
| in carbon is is in bis Hydro- To find A and Where C for Reserves Units Multiplier OF RESULTS OF ANALYSIS AND APPLICATION
2bU-S,) !
that
volume
assumed
determined
factor
extent
porosity
xX
10°
10°
10°
Among
recovery
type
can
following
N,-in
lists
to
feet
pt
CB
S,)/Bo]®
to
feet
of
stock-tank
been
that
takes
be
empirical
—_ meters
factor
= meters
reservoirs,
be
bbi/acre.
the
a
reservoirs.
of the
is
these,
25%,
factor,
terms
stock
AX r,
cubic
a
into
r,
by/ tte)”
30%.
of
barrels.
value
standard
Approximate
and
studies
equations
tank
of reservoir
formation
a
work
of
published
estimated
oil
oil
and
meters
for
gas
The
reservoir
gas
stock
cubic
and
productive
SE (pi/
.of
is
account
respectively:
function
barrels
oil
that
C for
the
water
from
feet
the
tank
recovery
of
200
the
Dy)!
of historical
the
Poston
logs.
parameters
drive
English
water-drive
formation
acres.
attempt,
factors
data,
The
MM
MM
system
BCF
formation
volumes
formation
that
Nin
saturation
and
has
to
m3
m3
MMSTB
(1984)
of
Find
are
a
(WD)
may
can
either
relate
mechanism,
and
be
be
of 30%.

bed
by
and
volume
hydrocarbon
units
volume
metric

thus
recovery

= 151
5 £2» Sy
Pa
°. For i “ 8.
Db;
= > 756
the
= ona
i 0.5 cp 1.25 250 md = .35% 20% I ‘following data: given the reservoir in a water-drive recovery the primary Calculate QUESTION #8.2 fractions. and S,, are and ¢ & is in darcys equations, both d= 0.1741. c = 0.3722, = b a pressure, = P» , pressure, at bubble-point Hop pressure, bubble-point factor at volume = oil formation By reservoirs, for
=
=
volume
volume
=
=
Because
1.5
750
2000
of
Oil
cp
FORMATION
of oil
psia
formation.
factor,
psia
0.1611,
0.0979,
41.82[6
B,.
The
-
viscosity
dissolved
bubble-point
It
VOLUME
recovered
is
gas
at
a
shrinkage
is
present
FACTORS
surface
in
is
function
oil
of
less
at
—
quantified
the
than
by
gas
the
reservoir
the
5,.)/Boo]®
oil
gravity,
volume

Ves
conditions,
of oil
in
the
‘the
formation