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62                       Schro Èdinger wave mechanics

                             Thus, the three-dimensional problem has been reduced to three one-dimen-
                             sional problems.
                               The differential equations (2.78) are identical in form to equation (2.34) and
                             the boundary conditions are the same as before. Consequently, the solutions
                             inside the box are given by equation (2.40) as
                                                    r 
                                                      2    n x ðx
                                             X(x) ˆ     sin     ,     n x ˆ 1, 2, 3, ...
                                                      a      a
                                                    r 
                                                      2    n y ðy
                                             Y(y) ˆ     sin     ,     n y ˆ 1, 2, 3, ...       (2:80)
                                                      b      b
                                                    r 
                                                      2    n z ðz
                                             Z(z) ˆ     sin     ,     n z ˆ 1, 2, 3, ...
                                                      c      c
                             and the constants E x , E y , E z are given by equation (2.39)
                                                        2 2
                                                       n h
                                                 E x ˆ  x   ,     n x ˆ 1, 2, 3, ...
                                                       8ma 2
                                                        2 2
                                                       n h
                                                        y
                                                 E y ˆ      ,     n y ˆ 1, 2, 3, ...           (2:81)
                                                       8mb 2
                                                        2 2
                                                       n h
                                                 E z ˆ  z   ,     n z ˆ 1, 2, 3, ...
                                                       8mc 2
                             The quantum numbers n x , n y , n z take on positive integer values independently
                             of each other. Combining equations (2.76) and (2.80) gives the wave functions
                             inside the three-dimensional box
                                                         r 
                                                           8    n x ðx   n y ðy   n z ðz
                                                   (r) ˆ     sin     sin      sin              (2:82)
                                                           v      a        b       c
                                            ø n x ,n y ,n z
                             where v ˆ abc is the volume of the box. The energy levels for the particle are
                             obtained by substitution of equations (2.81) into (2.79)
                                                                       2
                                                             h 2  n 2  n y  n 2
                                                          ˆ        x  ‡  ‡   z                 (2:83)
                                                   E n x ,n y ,n z  2  2    2
                                                            8m a      b    c


                             Degeneracy of energy levels
                             If the box is cubic, we have a ˆ b ˆ c and the energy levels become
                                                              h 2  2    2    2
                                                          ˆ      (n ‡ n ‡ n )                  (2:84)
                                                   E n x ,n y ,n z  2  x  y   z
                                                            8ma
                                                                       2
                                                                             2
                             The lowest or zero-point energy is E 1,1,1 ˆ 3h =8ma , which is three times the
                             zero-point energy for a particle in a one-dimensional box of the same length.
                             The second or next-highest value for the energy is obtained by setting one of
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