Page 13 - Partition & Adsorption of Organic Contaminants in Environmental Systems
P. 13

4    IMPORTANT THERMODYNAMIC PROPERTIES

                                     dE =  T dS -  P dV                   (1.8)

           For any other process, dq π TdS and  dw π PdV. However, the difference
           between TdS and PdV (i.e., dE) is a state function. Therefore, Eq. (1.8) holds
           for all processes, whether or not reversible.
              According to the second law of thermodynamics, the criterion for whether
           a process is taking place reversibly (i.e., at equilibrium) or spontaneously
           within a completely isolated system (i.e., the one at constant volume and inter-
           nal energy) is given as

                                        ( dS) EV  ≥ 0                     (1.9)
                                             ,
           that is, the overall entropy change of the system is zero for an equilibrium
           process but increases for a spontaneous process. The fact that (dS) E,V can never
           be less than zero is a consequence of the second law.
              Chemical processes of most interest usually take place at constant temper-
           ature and pressure. A new criterion is therefore required to indicate whether
           a process is reversible or spontaneous under this condition. If we now allow
           a process to take place initially in an isolated system and then adjust the tem-
           perature by reversible absorption (or emission) of heat and adjust the pres-
           sure by reversible expansion (or contraction) at constant temperature, the
           entropy change from the adjustment will be dq/T = (dE + PdV)/T. The change
           in entropy of the system, which is no longer an isolated system, after this
           adjustment will be

                              ( dS) TP  = ( dS)  E V  +  dE T P dV T     (1.10)
                                                   +
                                          ,
                                   ,
           Substituting Eq. (1.9) into Eq. (1.10) gives
                                                 - (
                             - (   ) EV  = dE P dV TdS ) T P  £ 0        (1.11)
                                           +
                              TdS
                                    ,
                                                        ,
           The quantities on both sides will therefore be negative for spontaneous
           processes, zero for equilibrium processes, and never positive.
              One can express the right side of Eq. (1.11) by defining a new state func-
           tion, G, the Gibbs function or Gibbs free energy, as
                                                    -
                                            -
                                 G =  E +  PV TS =  H TS                 (1.12)
           At constant temperature and pressure, one gets
                                 ( dG) TP  =  dE P dV T dS               (1.13)
                                                   -
                                             +
                                      ,
           From Eqs. (1.11) and (1.13) the condition that
                                        ( dG)  £ 0                       (1.14)
                                            TP
                                             ,
   8   9   10   11   12   13   14   15   16   17   18