Page 126 - Petrophysics 2E
P. 126

POROSITY         99


                             An expression similar to Equation 3.6 may be derived for estimating the
                             initial gas-in-place. In this case it is convenient to express the gas volume
                             in cubic feet. At standard conditions-is., P,,  = 14.7 psia and T,,  = 6O"F,
                             the initial gas-in-place in a volumetric reservoir is given by:



                                                                                           (3.7)



                             where Bgi, the initial gas formation volume factor in ft3/SCF, is calculated
                             from:



                                                                                           (3.8)


                            The  initial  gas  deviation  (also  called  compressibility)  factor,  zi,  is
                             calculated at  the  initial pressure  pi  of  the  gas  reservoir.  This factor
                             accounts for the difference between the actual and ideal gas volumes.

                            The reservoir temperature T is in degree Rankin (OR).
                             EXAMPLE


                               A volumetric gas reservoir has the following characteristics:


                            A = 1,320 acres                    T = 200°F
                            h=45ft                            Pi  = 4,000 psia
                            @  = 0.175                         zi  = 0.916
                            Si,  = 0.23


                            SOLUTION

                               The initial gas formation volume factor is:


                                          0.916(460 + 200)             ft3
                            Bgi = 0.02829                  = 0.004276-
                                               4,000                  SCF


                            The initial gas in place is:

                                                          1
                                        (1,320)(45)(0.175)( - 0.23)
                            G = 43,560                             = 81.539 x  lo9 SCF
                                                 0.004276
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