Page 263 - Petrophysics
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236    PETROPHYSICS: RESERVOIR ROCK PROPERTIES


                  Manipulating Equations 4.40, 4.54, and 4.55 yields a general relation-
                ship,  which  can  be  used  to  estimate the  cementation factor m  and
                Humble constant a:

                          1
                log @  = - - [log Rt - log (aR,)   - log IR]                  (4.58)
                         m


                Thus, a plot of  Cp vs.  Rt  on a log-log graph s,,ould  yield a straight line
                with a slope (- l/m) for 100% water-saturated zones, having constant
                resistivity index, IR and aR,.  Figure 4.24 shows such a plot for the case
                of a homogeneous sandstone oil reservoir.
                  The water zones, where IR = 1, form a straight line with a slope
                approximately equal to 2. When Cp  = 100% and IR = 1, Equation 4.58
                reduces to log Rt  = log(aR,).  Therefore, the product aR,  can be deter-
                mined directly from Figure 4.24 by simply extrapolating the straight line
                to Cp  = 100% and reading the corresponding value of  aR,  on the Rt
                axis. Knowing the water resistivity R,,   from Figure 4.24  for instance,
                one can calculate a. The log-log  plot of  Cp vs.  Rt  also can be used to
                estimate the water saturation of  the reservoir from Equation 4.55,  i.e.,
                S, =        by assuming the cementation factor m and the saturation
                exponent n are equal. The limitation of this equation is that a significant
                number  of  water-bearing zones  of  constant a,  m,  and  R,   must  be
                available [ 181.





                   100














                                                                                  I


                     0.1                  1                  10                  100
                                          Total Resistivity, ohm-m

                           Figure 4.24. Porosity us. total resistivity for S,   = 100%.
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