Page 478 - Petrophysics
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446    PETROPHYSICS: RESERVOIR ROCK PROPERTIES


                    The dimensionless pressure of a well producing at a constant rate in the
                    infinite-acting portion of the pressure vs. time curve, i.e., during unsteady
                     state, is approximated by:
                                        2  )
                          1    5.92 x  10-*kt
                          2        @CLctrw                                        (7.88)

                     In this case, the pressure drop, Ap, in Equation 7.78 is actually (pi - pw),
                     where pi is the initial reservoir pressure. Equation 7.88 is applicable only
                     if (0.0002637 kt/@yctr:)  > 100.

                     EXAMPLE

                       A Cartesian plot of pressure data recorded during a constant rate well
                     test in a water driven oil reservoir yielded a pseudosteady-state straight
                     line with slope  -0.26  psihr.  Other pertinent reservoir and well data
                     include the following:

                     A = 7.72 acres               qs,  = 350 STB/D
                     h=49ft                        Be  = 1.136 bbl/STB

                                                                 6
                     @ = 0.23                      CE = 17 x  10-  psi-'

                       Determine  the  drainage boundary  index  f.  Is  the  pressure  at  the
                     drainage boundary constant?


                     SOLUTION

                       The drainage boundary index f is calculated from a rearranged form of
                     Equation 7.87:



                                                                                  (7.89)

                     where the drainage pore volume is:


                     Vp  = Ah@ = 7.72 x 43,560 x 49 x 0.23 = 3.79 x lo6 ft3

                     The boundary index is:

                              17 x lo6 x 3.79 x lop6
                                                      (-0.26)  = 0.82
                     f=l+                            1
                               0.234 x 350 x  1.136
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