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7.9 Lithospheric stretching of finite duration    219

            way to do modeling with a laterally varying strain rate is to approximate the strain rate as a
            piecewise constant. The lithosphere is then made discrete using columns, where each one
            has its own (time-dependent) strain rate.
              An x-dependent strain rate implies that the stretching factor β also becomes x-
            dependent. In a Lagrangian coordinate frame (that follows the lateral movements) both
            the strain rate and the β-factor are only dependent on t. We have that G = (1/β)(Dβ/dt)
            in a Lagrangian coordinate frame. When the time derivative is brought from the Lagrangian
            frame to the Euler coordinate x we get
                                       1 Dβ    1 ∂β    ∂β ∂x

                                   G =      =       +                          (7.90)
                                       β dt    β ∂t    ∂x ∂t
            where ∂x/∂t = v x . From mass conservation (7.79)wealsohavethat G = ∂v x /∂x, which
            gives the following equation for the β-factor:
                                     ∂β   ∂β       ∂v x
                                        +    v x − β   = 0.                    (7.91)
                                      ∂t  ∂x       ∂x
            More complicated flow patterns result if the strain rate is allowed to vary with both the
            x- and the z-coordinates.


            Exercise 7.13 The upper and brittle part of the lithosphere may deform by normal faulting
            and rotation of fault blocks during extension. Figure 7.16 shows how the “domino-type” of
            fault block rotation accommodates the stretching. We notice that large displacement along
            a few faults is the same as little displacement along many faults.
            (a) Show that the β-factor is
                                                 1
                                            β =                                (7.92)
                                                sin φ
            when the blocks make an angle φ with the horizontal.
                                                    ◦
            (b) What is the angle φ when β is 2? (Answer: 30 )
            (c) Assume that the fault blocks rotate to an angle φ 1 during a first rift phase and then
            further to an angle φ 2 <φ 1 during a second rift phase. (The angle φ decreases from π/2










                                                           φ

                        Δx                    Δl
                         (a)                     (b)              (c)
            Figure 7.16. (a) Normal faulting. (b) Domino style rotation of the fault blocks. (c) A large number of
            smaller faults makes the displacement at each fault less.
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