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92    ENERGY AND THE FIRST LAW OF THERMODYNAMICS

                      The expression in Equation (3.6) is really a partial differential: the value of U depends
                      on both T and V , the values of which are connected via Equation (1.13). Accordingly,
                      we need to keep one variable constant if we are unambiguously to attribute changes in
                      C V to the other. The two subscript ‘V ’ terms tell us C is measured while maintaining
                      the volume constant. When the derivative is a partial derivative, it is usual to write
                      the ‘d’as‘∂’.
                                        We call C V ‘the heat capacity at constant volume’. With the
              We also call C V the    volume constant, we measure C V without performing any work
              isochoric heat capacity.  (so w = 0), so we can write Equation (3.6) differently with dq
                                      rather than dU.
                                        Unfortunately, the value of C V changes slightly with tempera-
                                      ture; so, in reality, a value of C V is obtained as the tangent to
              A tangent is a straight  the graph of internal energy (as y) against temperature (as x); see
              line that meets a curve  Figure 3.5.
              at a point, but not       If the change in temperature is small, then we can usually assume
              does cross it. If the   that C V has no temperature dependence, and write an approximate
              heat capacity changes   form of Equation (3.6), saying
              slightly with temper-
              ature, then we obtain

              the value of C V as the                        U
                                                     C V =                                  (3.7)
              gradient of the tangent                        T
              to a curve of  U (as y)
              against T (as x).
                                        Analysing Equations (3.6) and (3.7) helps us remember how the
                                                                    −1
                                      SI unit of heat capacity C V isJK . Chemists usually cite a heat
                      capacity after dividing it by the amount of material, calling it the specific heat capacity,
                                                      −1 −1
                      either in terms of J K −1  mol −1  or J K g . As an example, the heat capacity of water
                               −1 −1
                      is 4.18 J K g , which means that the temperature of 1 g of water increases by 1 K
                      for every 4.18 J of energy absorbed.
                      SAQ 3.1 Show that the molar heat capacity of water is 75.24 J K   −1  mol −1
                      if C V = 4.18 J K −1 −1 . [Hint: first calculate the molar mass of H 2 O.]
                                       g

                                                Tangential gradient = heat capacity, C V




                                            U





                                                          T

                      Figure 3.5 The value of the heat capacity at constant volume C V changes slightly with temper-
                      ature, so its value is best obtained as the gradient of a graph of internal energy (as y)against
                      temperature (as x)
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