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                132
               Chapter 4                    Exercise
               Material Equilibrium
                                            Write the phase-equilibrium conditions for a crystal of NaCl in equilibrium with
                                            an aqueous solution of NaCl. (Answer: m s    m aq  .)
                                                                              NaCl   NaCl




                                          4.8           REACTION EQUILIBRIUM
                                         We now apply the material-equilibrium condition to reaction equilibrium. Let the re-
                                         action be
                                                           aA   bA      . . . S eA   fA m 1     . . .       (4.92)
                                                              1
                                                                    2
                                                                                m
                                         where A , A , . . . are the reactants, A , A  , . . . are the products, and a, b, . . ., e, f, ...
                                                1  2                    m  m 1
                                         are the coefficients. For example, for the reaction
                                                              2C H   15O S 12CO   6H O
                                                                   6
                                                                 6
                                                                          2
                                                                                   2
                                                                                         2
                                         A   C H , A   O , A   CO , A   H O and a   2, b   15, e   12, f   6. The sub-
                                           1   6  6  2    2  3     2  4    2
                                         stances in the reaction (4.92) need not all occur in the same phase, since the material-
                                         equilibrium condition applies to several-phase systems.
                                             We adopt the convention of transposing the reactants in (4.92) to the right side of
                                         the equation to get
                                                         0 S  aA   bA      . . .    eA   fA m 1     . . .   (4.93)
                                                                       2
                                                                 1
                                                                                   m
                                         We now let
                                                      n    a,  n    b,  . . . ,  n   e,  n m 1    f,  . . .
                                                       1
                                                                                 m
                                                                 2
                                         and write (4.93) as
                                                      0 S n A   n A      . . .    n A   n m 1 A m 1     . . .
                                                                               m
                                                                                  m
                                                                     2
                                                              1
                                                                   2
                                                           1
                                                                        0 S  a  n A i                       (4.94)
                                                                                i
                                                                             i
                                         where the stoichiometric numbers n (nu i) are negative for reactants and positive
                                                                          i
                                         for products. For example, the reaction 2C H   15O → 12CO   6H O becomes
                                                                              6  6     2         2     2
                                         0 →  2C H   15O   12CO   6H O, and the stoichiometric numbers are n
                                                  6  6     2        2     2                                 C 6 H 6
                                          2, n   15, n        12, and n     6. The stoichiometric numbers (also called
                                              O 2        CO 2          H 2 O
                                         stoichiometric coefficients) are pure numbers with no units.
                                             During a chemical reaction, the change  n in the number of moles of each sub-
                                         stance is proportional to its stoichiometric number n, where the proportionality con-
                                         stant is the same for all species. This proportionality constant is called the extent of
                                         reaction j (xi). For example, in the reaction N   3H → 2NH , suppose that 20
                                                                                   2     2        3
                                         mol of N reacts. Then 60 mol of H will have reacted, and 40 mol of NH will have been
                                                2                     2                             3
                                         formed. We have  n   20 mol   1(20 mol),  n   60 mol   3(20 mol),
                                                           N 2                          H 2
                                          n      40 mol   2(20 mol), where the numbers  1,  3, and 2 are the stoichiomet-
                                            NH 3
                                         ric numbers. The extent of reaction here is j   20 mol. If x moles of N reacts, then
                                                                                                      2
                                         3x moles of H will react and 2x moles of NH will be formed; here j   x mol and
                                                     2                           3
                                          n   x mol,  n   3x mol,  n          2x mol.
                                            N 2           H 2            NH 3
                                             For the general chemical reaction 0 →   n A [Eq. (4.94)] undergoing a definite
                                                                               i  i  i
                                         amount of reaction, the change in moles of species i,  n , equals n multiplied by the
                                                                                         i        i
                                         proportionality constant j:
                                                                    ¢n   n   n   n j                       (4.95)*
                                                                               i,0
                                                                           i
                                                                       i
                                                                                     i
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