Page 139 - Pipeline Rules of Thumb Handbook
P. 139

126     Pipeline Rules of Thumb Handbook

         Voltage drop on circuits using 600 V. copper conductors in steel conduit


           To determine the voltage drop, multiply the length in feet  loss. This table takes into consideration reactance on AC cir-
         of one conductor by the current in amperes and by the  cuits and resistance of the conductor. Unless otherwise noted,
         number listed in the table for the type of system and power  the table is based on 60Hz.
         factor and divide the result by 1,000,000 to obtain the voltage


                                             Three Phase                               Single Phase
                                         Lagging Power Factor                      Lagging Power Factor
            Wire      Direct
            Size     Current   100%     90%      80%     70%      60%     100%     90%     80%     70%      60%

             14       6,100    5,280    4,800   4,300    3,780   3,260    6,100   5,551   4,964    4,370    3,772
             12       3,828    3,320    3,030   2,720    2,400   2,080    3,828   3,502   3,138    2,773    2,404
             10       2,404    2,080    1,921   1,733    1,540   1,340    2,404   2,221   2,003    1,779    1,547
              8       1,520    1,316    1,234   1,120    1,000     880    1,520   1,426   1,295    1,159    1,017
              6        970       840     802      735     665      590     970      926     850      769     682
              4        614       531     530      487     445      400     614      613     562      514     462
              3        484       420     425      398     368      334     484      491     460      425     385
              2        382       331     339      322     300      274     382      392     372      346     317
              1        306       265     280      270     254      236     306      323     312      294     273
              0        241       208     229      224     214      202     241      265     259      247     233
             00        192       166     190      188     181      173     192      219     217      209     199
            000        152       132     157      158     155      150     152      181     183      179     173
           0000        121       105     131      135     134      132     121      151     156      155     152
            250M       102        89     118      123     125      123     103      136     142      144     142
            300M        85        74     104      111     112      113      86      120     128      130     131
            350M        73        63      94      101     105      106      73      108     117      121     122
            400M        64        55      87       95      98      100      64      100     110      113     116
            500M        51        45      76       85      90       92      52       88      98      104     106
            600M        43        38      69       79      85       87      44       80      91       98     101
            700M        36        33      64       74      80       84      38       74      86       92      97
            750M        34        31      62       72      79       82      36       72      83       91      95
            800M        32        29      61       71      76       81      33       70      82       88      93
            900M        28        26      57       68      74       78      30       66      78       85      90
           1000M        26        23      55       66      72       76      27       63      76       83      88



         Determine the most economical size for electric power conductors


           To calculate quickly the most economical size copper wire  as well as economics. Once these are considered, the most
         for carrying a specified current load, use the formula:  economical size conductor is that for which the annual energy
                                                               cost equals the copper cost. This method can be used for
                    C e ¥  t
          A = ()( I)                                           other metallic conductors.
              59
                    C c ¥  F
                                                                 Example. Determine the most economical size copper
         where A = Conductor cross-sectional area (circular mils)
                                                               conductor for an installation operating 365 days a year, 8
                I = Current load (amperes)
                                                               hours per day, with a 100 ampere load. Energy costs are
               C e = Cost of electrical power (cents per KWH)
                                                               $0.00875 per KWH. Fixed charges are 23 percent, consider-
               C c = Cost of copper (cents per lb)
                                                               ing a five-year amortization with 3 percent for insurance and
                t = Hours of service per year
                                                               taxes. Copper costs $0.46 per lb.
                F = Factor for fixed charges (amortization, insurance,
                   taxes, etc.)                                             0 00875  ¥ 365  ¥ 8
                                                                             .
                                                                    59
                                                                A = ()(100 )
                                                                                .
                                                                                     .
         Selection of the proper size electric conductor will depend on        046  ¥ 0 23
                                                                     ,
         the load to be carried and the mechanical strength required,  = 91 686 circular mils
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