Page 47 - Principles of Applied Reservoir Simulation 2E
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32  Principles  of Applied  Reservoir  Simulation


                     mass entering the block - mass leaving the block
                          = accumulation of mass in the block.
         If the block has length A*, width Ay, and depth Az, then we can write the mass
         entering the block in a time interval A/ as

                                        (
                 |  (',/  )  AvAz+ (j  }  AxAz + j  }  AjcAv  A/  =  Mass in  (4,1)
                 I  '<  x  ' x  \  y I  v  \  z  I :  "  \
         where we have generalized to allow flux in the y  and z directions as well, The
                    denotes the x direction flux at location*, with analogous meanings
         notation (J x) x
         for  the remaining terms,
              Corresponding to mass entering is a term for mass exiting which has the
         form
                             +
                           z
                                                        A A A
                                     A A
              lW*.*,*y*  (^W * *             +  (^) A, * ^ '
                                                   2+
                                                                     (4.2)
                          +  gAxAyAzA/    =  Mass out
         We have added a source/sink term q which represents  mass flow  into  (source)
         or out of (sink) a well. A producer is represented by q > 0, and an injector by
         q<0.
              Accumulation of mass in the block is the change in concentration  of phase
         <! (C 4) in the block over the time interval A?. If the concentration  C t is defined
         as  the  total mass  of  phase  0  (oil, water,  or  gas)  in the  entire reservoir block
         divided by the block volume, then the accumulation  term  becomes

                [(^X+A*  ~  (C^JAjtAyAz    =  Mass accumulation      (43)

              Using Eqs. (4.1) through  (4.2) in the mass conservation  equality
                        Mass in - Mass out = Mass accumulation
         gives
                  [(/^AyAz    H-  (J^AjcAz  +  0/ Z ) Z A*A7]A?
                                       A A +
            -  lW .***y*   z  +  (^W * *         W ^ &x&y]&t       (4.4)
                  x
                                                   z z
                 -  ^AxAyAzA/    =  [(C ( )^ Ar  -  (C f ),]A*A;pAz

        Dividing Eq. (4.4) by AxAyAzA/ and rearranging gives
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