Page 43 - Probability Demystified
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32                                        CHAPTER 2         Sample Spaces

                                   Notice that the sample space consists of ordered pairs of numbers. The
                                 outcome (4, 2) means that a 4 was obtained on the first die and a 2 was
                                 obtained on the second die. The sum of the spots on the faces in this case is
                                 4 þ 2 ¼ 6. Probability problems involving rolling two dice can be solved using
                                 the sample space shown in Figure 2-11.

                                 EXAMPLE: When two dice are rolled, find the probability of getting a sum
                                 of nine.

                                 SOLUTION:
                                 There are four ways of rolling a nine. They are (6, 3), (5, 4), (4, 5), and (3, 6).
                                 The sample space consists of 36 outcomes. Hence,

                                             4    1
                                      Pð9Þ¼    ¼
                                             36   9

                                 EXAMPLE: When two dice are rolled, find the probability of getting
                                 doubles.


                                 SOLUTION:
                                 There are six ways to get doubles. They are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5),
                                 and (6, 6); hence
                                                   6    1
                                      PðdoublesÞ¼     ¼
                                                   36   6


                                 EXAMPLE: When two dice are rolled, find the probability of getting a sum
                                 less than five.

                                 SOLUTION:
                                 A sum less than five means a sum of four, three, or two. There are three ways
                                 of getting a sum of four. They are (3, 1), (2, 2), and (1, 3). There are two ways
                                 of getting a sum of three. They are (2, 1), and (1, 2). There is one way of
                                 getting a sum of two. It is (1, 1). The total number of ways of getting a sum
                                 less than five is 3 þ 2 þ 1 ¼ 6. Hence,
                                                           6   1
                                      P(sum less than 6) ¼   ¼
                                                          36   6
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