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272    5. Concepts of Stochastic Convergence

                                    5.2.10 Consider a sequence of real valued random variables {T ; n > k},
                                                                                          n
                                 and suppose that               as n → ∞. Is it true that for some real
                                 number a, the random variable          as n → ∞? {Hint: Can one apply
                                 Slutsky’s Theorem after taking the natural logarithm?}
                                    5.2.11 (Exercise 5.2.10 Continued) Let X , ..., X  be iid Poisson(λ) with λ
                                                                      1     n
                                 > 0, and let           for n > k. Show that                as n →
                                 ∞. Also, find the number c(> 0) such that      as n → ∞.
                                    5.2.12 Consider a sequence of real valued random variables {T ; n ≥ 1},
                                                                                          n
                                 and suppose that            as n → ∞. Let us define X  = I(T  > 1/2a),
                                                                                    n    n
                                 n ≥ 1. Does            as n → ∞? Suppose that Y  = I(T  > 3/2a), n ≥ 1.
                                                                              n     n
                                 Does            as n → ∞? {Hint: Try and apply the Definition 5.2.1 di-
                                 rectly. Can one use the Markov inequality here?}
                                    5.2.13 (i) Consider the two sequences of random variables {U ; n ≥ 1}
                                                                                          n
                                 and {V ; n ≥ 1} respectively defined in (5.2.6)-(5.2.7). Verify that
                                       n
                                        as n → ∞. Using Theorem 5.2.4, it will immediately follow that
                                            and       as n → ∞.
                                    (ii) Additionally suppose that U  and V  are independent for all n ≥ 1. In
                                                                     n
                                                               n
                                 this situation, first obtain the probability distributions of    and U  V .
                                                                                              n
                                                                                                n
                                 Hence, show directly, that is without appealing to Slutsky’s Theorem, that
                                            and           as n → ∞.
                                    5.2.14 Suppose that (X , Y ), i = 1, ..., 2n, are iid N (0, 0, 1, 1, ρ) with –1
                                                                               2
                                                          i
                                                       i
                                 < ρ < 1. Recall the bivariate normal distribution from the Section 3.6. Let us
                                 denote

                                 with i = 1, 2, ..., n. Consider now the sample mean         , and
                                 denote
                                        (i)  Show that the U ’s are iid Bernoulli with p = 1/2 (1 + ρ );
                                                         i
                                        (ii) Show that      as n → ∞.
                                    {Hint: Note tht p =  P(U  = 1) =  P(X Y  +  X Y  > 0). But, one can
                                                           1
                                                                      1
                                                                        1
                                                                             2
                                                                               2
                                                                   2
                                 write, for example, X Y  = ¼{(X  + Y )  – (X  – Y ) }, so that p = P{(X  +
                                                                              2
                                                                  1
                                                              1
                                                    1
                                                                            1
                                                                                               1
                                                      1
                                                                        1
                                 Y )  – (X  – Y )  + (X  + Y )  – (X  – Y )  > 0} = P{(X  + Y )  + (X  + Y ) 2
                                                                    2
                                    2
                                                         2
                                                                                      2
                                              2
                                                                                     1
                                                                                1
                                             1
                                                    2
                                         1
                                                                                                2
                                  1
                                                                                           2
                                                                   2
                                                              2
                                                        2
                                                                                   2
                                 > (X  –  Y )  + (X  –  Y ) }. Verify that  U = (X  +  Y )  + (X  +  Y )  is
                                                       2
                                           2
                                                                                               2
                                                                                             2
                                                                                        2
                                          1
                                     1
                                                 2
                                                      2
                                                                            1
                                                                                 1
                                                                       2
                                 independent of V = (X  – Y )  + (X  – Y ) . Find the distributions of U
                                                            2
                                                                 2
                                                                      2
                                                      1
                                                          1
                                 and V. Then, rewrite p as the probability of an appropriate event defined
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