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CHAP. 22]                     INVERSE LAPLACE TRANSFORMS                              225



                                                                            m
            The method is carried  out as follows.  To each factor of b(s) of the form  (s -  a) , assign a sum of m  frac-
         tions, of the form




                                              p
         To each factor of b(s)  of the form (s 2  + bs + c) , assign a sum  of p  fractions, of the  form





         Here A;, Bj, and C k(i=  1, 2,..., m;j, k= 1, 2,...,p)  are constants which still must be determined.
            Set the original fraction a(s)lb(s)  equal to the sum of the new fractions just constructed. Clear the resulting
         equation of fractions and then equate coefficients of like powers of s, thereby  obtaining  a set of simultaneous
         linear  equations in the unknown constants A t, Bj, and C k. Finally, solve these equations for A t, Bj, and C k. (See
         Problems  22.11 through 22.14.)


         MANIPULATING NUMERATORS
            A  factor  s -  a in  the numerators  may be  written in  terms  of the factor  s -  b,  where  both  a  and b are
         constants, through the identity s -  a = (s -  b) + (b -  a). The multiplicative constant a in the numerator may be
         written explicitly in terms of the multiplicative constant b through the identity




         Both identities  generate recognizable inverse Laplace  transforms when they are combined with:
         Property  22.1.  (Linearity).  If  the  inverse Laplace  transforms of  two functions F(s) and  G(s)  exist, then
                                    for  any constants c l and c 2,



         (See Problems 22.4 through 22.7.)



                                           Solved   Problems


         22.1.  Find

                  Here  F(s)  = Us.  From  either  Problem  21.4 or  entry  1  of  Appendix  A,  we  have  ^{1} = Us.  Therefore,
                 l
               £- {lls}  = 1.

         22.2.  Find

                  From either Problem 21.6 or entry 7 of Appendix A with a = 8, we have






               Therefore,
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