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CHAP.  26]                   SOLUTIONS BY MATRIX METHODS                             255



         since the former equation  involves one less matrix multiplication. However, the integrals  arising in  (26.3) are
         generally more difficult  to evaluate than those in  (26.2).



         SOLUTION WITH NO INITIAL CONDITIONS

            If no initial  conditions  are prescribed, the solution of  x(?) = Ax(?) + f (?)  is




         or, when f(t)  = 0,


         where  k  is  an  arbitrary  constant  vector. All  constants  of integration  can be  disregarded  when computing  the
         integral in Eq. (26.5), since they are already included  in k.





                                           Solved Problems





         26.1.  Solve x + 2x-Sx  = 0;x(l)  = 2, i(l)=3.
                  From Problem 17.2, this initial-value problem is equivalent to Eq.  (26.1)  with





                                                             A(
               The  solution to this system is given by Eq.  (26.4).  For this A, e  is given in Problem 16.2; hence,






               Therefore,
















               and the solution to the original initial-value problem is
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