Page 222 - Schaum's Outline of Theory and Problems of Applied Physics
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CHAP. 17]                            FLUIDS IN MOTION                                 207



                                                                             2
               (b) The same procedure is followed here, but first it is necessary to convert 40 lb/in. to its equivalent in pounds
                   per square foot:
                                                               2
                                                     lb      in.
                                         p 2 − p 1 = 40   144    = 5760 lb/ft 2
                                                    in. 2    ft 2
                   Hence

                                                   (2)(5760) lb/ft 2
                                              v 1 =            = 77 ft/s
                                                    1.94 slugs/ft 3

        SOLVED PROBLEM 17.14
              A horizontal pipe 1 in. in radius is joined to a pipe 4 in. in radius, as in Fig. 17-3. (a) If the velocity
                                        3
                                                                                            2
              of seawater (d = 2.00 slugs/ft ) in the small pipe is 20 ft/s and the pressure there is 30 lb/in. , find
              the velocity and pressure in the large pipe. (b) What is the rate of flow through the pipe in pounds
              per minute?



                                                                    4 in.
                                   1 in.   1           2





                                                 Fig. 17-3


                                                                                           2
              (a) The cross-sectional areas of the pipes are in the same ratio as the squares of their radii, since A = πr . From
                  v 1 A 1 = v 2 A 2 we obtain
                                             A 1   r 1 2     ft     (1in.) 2
                                       v 2 = v 1  = v 1  2  = 20    = 1.25 ft/s
                                                   r       s  (4in.) 2
                                             A 2    2
                  Because both pipes are horizontal, h 1 = h 2 , and Bernoulli’s equation becomes

                                               lb      in.    1     slugs     ft        ft
                                                         2                       2         2
                                   2
                               1


                      p 2 = p 1 + d v − v  2  = 30  144    +      2        20    − 1.25
                               2   1   2      in. 2    ft 2   2      ft 3     s         s
                         = 4718 lb/ft 2
                  which is
                                                   4718 lb/ft 2
                                               p 2 =    2  2  = 33 lb/in. 2
                                                   144 in. /ft
                                                                            3
                                                  2
                                                                   2
              (b)                  R = v 1 A 1 = (v 1 )(πr ) = (20 ft/s)(π)(  12 1  ft) = 0.436 ft /s
                                                  1
                                3
                  Since dg = 64 lb/ft and 1 min = 60 s, the rate of flow in the required units is
                                                       3
                                              3
                                        (0.436 ft /s)(64 lb/ft )(60 s/min) = 1674 lb/min
        VISCOSITY
        The viscosity of a fluid is an internal friction that prevents adjacent layers of the fluid from sliding freely past each
                                                                                                2
        other. The symbol of viscosity is η, the Greek letter eta, and its SI unit is the poise (P), where 1 P = 1N·s/m .
        The viscosities of liquids decrease with temperature; those of gases increase.
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