Page 268 - Schaum's Outline of Theory and Problems of Applied Physics
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CHAP. 21]                            THERMODYNAMICS                                   253



                  High-temperature reservoir                      Expansion valve

                          T 2

                   Heat                               Condenser
                  exhaust  Q 2
                                                                      Evaporator

             Refrigerator             Energy
                                      input
                                 W
                   Heat
                   input  Q 1
                                                                                     Refrigerant vapor
                                                                   Compressor
                                                                                     Refrigerant liquid
                          T 1
                  Low-temperature reservoir   Fig. 21-10.  (From Modern Technical Physics, 6th Ed., Arthur
                                              Beiser, c  1992. Reprinted by permission of Pearson Education,
                        Fig. 21-9             Inc.)



            3. The liquid refrigerant now goes into the expansion valve, from which it emerges at a lower pressure and
               temperature.
            4. In the evaporator the cool liquid refrigerant absorbs heat from the storage chamber and vaporizes.
               Farther along in the evaporator the refrigerant vapor absorbs more heat and becomes warmer. The warm
               vapor then goes back to the compressor to start another cycle.

            In Step 4 of this cycle, heat is extracted from the storage chamber by the refrigerant. In Step 1, work
        is done on the refrigerant by the compressor. In Step 2, heat from the refrigerant leaves the system. A re-
        frigerator might remove two or more times as much heat from its storage chamber as the amount of work
        done.
            If a refrigerator absorbs heat Q 1 at the absolute temperature T 1 and ejects heat Q 2 at the absolute temperature
        T 2 , its coefficient of performance (CP) is given by
                                          heat absorbed  Q 1    Q 1
                                    CP =             =     =
                                           work done    W     Q 2 − Q 1
        In an ideal refrigerator, which is a Carnot engine run backward, Q 1 /Q 2 = T 1 /T 2 and

                                                         T 1
                                            CP(ideal) =
                                                       T 2 − T 1


        SOLVED PROBLEM 21.13
              In an effort to cool a kitchen during the summer, the refrigerator door is left open and the kitchen’s door
              and windows are closed. What will happen?
                  Since no refrigerator can be completely efficient, more heat is exhausted by the refrigerator into the kitchen
              than is extracted from the kitchen. The net effect, then, is to increase the kitchen’s temperature.


        SOLVED PROBLEM 21.14
              A 1-kW refrigerator whose coefficient of performance is 2.0 takes heat from a freezer compartment at
                                     ◦
                  ◦
              −20 C and exhausts it at 40 C. How does its CP compare with that of an ideal refrigerator?
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