Page 282 - Schaum's Outline of Theory and Problems of Signals and Systems
P. 282

CHAP.  51        FOURIER ANALYSIS OF TIME SIGNALS AND SYSTEMS



                 (c)   First, we  rewrite  H(w) in standard form as
                                                             lO(1 + jw)
                                              H(o) =
                                                      (1 + jw/lO)(l  + jo/100)
                       Then






                       Note  tha  ~t there  are  three  corner  frequencies,  o = 1, w = 10, and  w = 100. A  ,t corner
                       frequency w = 1
                               H(~)I,,  = 20 + 20loglO& - 2010g,,m6-  - 2010g,~~ % 23 dB

                       At corner frequency w = 10
                                ~(10)~~,=20+20lo~,,~-201o~,,&- 2010glomb 37dB
                       At corner frequency w = 100



                       The  Bode  amplitude  plot  is  sketched  in  Fig. 5-30(a).  Each  term  contributing  to  the
                       overall  amplitude is also indicated. Next,
                                                                  w          0
                                           OH(w) = tan-'  w - tan-'  - -tan-'  -
                                                                  10        100
                       Then






                       and
                                    eH(l)  = tan-'(1)  - tan-'(0.1)  - tan-'(0.01)  = 0.676 rad

                                   eH(lO) = tan-'(10)  - tan-'(1)  - tan-'(0.1)  = 0.586 rad
                                  8,(100)  = tan-'(100)  - tan-'(10)  - tan-'(1)  = -0.696  rad
                       The plot of  eH(w) is sketched in Fig. 5-30(b).


           5.48.  An ideal ( -7r/2)  radian (or -90")  phase shifter (Fig. 5-31) is defined by the frequency
                 response





                 (a)  Find the impulse response  h(t ) of  this phase shifter.
                 (6)  Find the output  y(t) of  this phase shifter due to an arbitrary input  x(t).
                 (c)  Find the output  y(t) when  x(t) = cos oot.

                 (a)  Since  e-j"l2  = -j and  eJ"/2 = j,  H(w) can be rewritten as
                                                    H(w) = -jsgn(w)                         (5.170)
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