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270                               DECISION  THEORY                           [CHAP.  8



         8.4.   Consider the binary  decision problem  of  Prob. 8.3. We  modify  the  decision rule such that we
               reject H, if x 2 c.

              (a)  Find the value of c such that the probability of a Type I error a = 0.05.
              (b)  Find the probability of a Type I1 error /I when p,  = 55 with the modified decision rule.

               (a)  Using the result of part (b) in Prob. 8.3, c is selected such that [see Eq. (8.27)J
                                           a = g(50) = P(x 2 c; p = 50) = 0.05
                  However, when p = 50, X = N(50; 4), and [see Eq. (8.2811



                  From Table A (Appendix A), we have 0(1.645)  = 0.95. Thus
                                    c - 50
                                    --  - 1.645    and   c = 50 + 2(1.645) = 53.29
                                      2
               (b)  The power function g(p) with the modified decision rule is




                  Setting p = p, = 55 and using Table A (Appendix A), we obtain






                  Comparing with  the  results  of  Prob.  8.3,  we  notice that  with  the change of  the  decision  rule,  a is
                  reduced from 0.1587 to 0.05, but j3 is increased from 0.0668 to 0.1963.



         8.5.   Redo Prob. 8.4 for the case where the sample size n = 100.
              (a)  With n  = 100, we have




                  As in part (a) of Prob. 8.4, c is selected so that
                                           a= g(50) = P(8 2 c; p = 50) = 0.05
                  Since X = N(50; I), we have



                  Thus                    c - 50 = 1.645   and   c = 51.645
              (b)  The power function is






                  Setting  p = p, = 55 and using Table A (Appendix A), we obtain
                                  fl = Pn = 1 - g(55) = (D(51.645 - 55) = @(-3.355)  x 0.0004
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