Page 79 - Schaum's Outlines - Probability, Random Variables And Random Processes
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RANDOM  VARIABLES                            [CHAP  2




                   Substituting B = (a < X 5 b) in Eq. (2.59), we have
                                                             P((X I x) n (a < X I b)}
                             FX(x(a<XIb)=P(X<xlac~Ib)=
                                                                  P(a < X I b)


               Now

               Hence,
                                                                       xla







               By  Eq. (2.63),  the  conditional  pdf of X  given  a < X I b  is  obtained  by  differentiating Eq.  (2.104) with
               respect to x. Thus,


                               Fx(x






         2.51.  Recall  the  parachuting  sky  diver  problem  (Prob. 2.48).  Find  the  probability  of  the  sky diver
               landing within a  10-m radius from the center of  the target  area given that the landing is within
               50 m from the center of the target area.
                  From Eq. (2.75) (Prob. 2.23) with a2 = 100, we have


               Setting x = 10 and b = 50 and a = - cc in Eq. (2.104), we obtain









         2.52.  Let X  = N(0; 02). Find E(X I X > 0) and Var(X 1 X > O),
                  From Eq. (2.52), the pdf of X = N(0; a2) is




               Then by Eq. (2.105),







               Hence,
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