Page 39 - Theory and Problems of BEGINNING CHEMISTRY
P. 39

28                        MATHEMATICAL METHODS IN CHEMISTRY                       [CHAP. 2


               2.29.  Make the following conversions:

                                                                              3
                                     2
                     (a) Change 6.3 cm to m 2                  (e) Change 1.7 m to kL
                                                                              2
                                     3
                     (b) Change 13 cm to m 3                   (f ) Change 3.3 m to cm 2
                     (c) Change 9.2 L to cm 3                  (g) Change 219 mL to cm 3
                                     3
                     (d) Change 9.6 dm to L
                                             2
                                       1m                                  1kL
                     Ans.  (a)6.3cm 2         = 0.000 63 m 2     (e)1.7m 3       = 1.7kL
                                      100 cm                               1m 3
                                                                                   2
                                             3
                                                                           100 cm
                                      1m                                 2                   2
                           (b)13 cm 3        = 0.000 013 m 3     (f)  3.3m         = 33 000 cm
                                     100 cm                                  1m
                                    1000 cm                                              3
                                          3                                  1cm 3
                           (c)9.2L           = 9200 cm 3         (g) 219 mL       = 219 cm
                                      1L                                    1mL

                                       1L
                           (d)9.6dm 3       = 9.6L
                                      1dm 3
               2.30. Give the volume corresponding to each of the following in terms of a dimension involving length cubed:
                     (a) 1 kL, (b)2L,(c) 3 mL, and (d)4 µL.
                     Ans.  (a)1 m 3  (b)2dm 3  (c)3cm 3  (d)4mm 3
               EXPONENTIAL NUMBERS
                                       3
               2.31. In the number 5.0×10 , identify (a) the coefficient, (b) the exponent, (c) the base, and (d) the exponential
                     part.
                     Ans.  (a) 5.0  (b)3  (c)10 (d)10 3
               2.32. What is the meaning of each of the following: (a) ten squared, (b) ten cubed, (c) ten to the fourth power?

                     Ans.  (a)10 2  (b)10 3  (c)10 4
               2.33. Which of the following numbers are in standard exponential form?

                     (a)11.0 × 10 −3                           (f)  0.12 × 10 5
                     (b)6.7 × 10 0                             (g)0.1 × 10 5
                     (c)3 × 10 7                               (h)4.4 × 10 3
                     (d)0.77 × 10 7                            (i)  1.0 × 10 4
                     (e)1.23 × 10 −4

                     Ans.  (b), (c), (e), (h), and (i)
                                                                                                 6
                                                                                     3 2
               2.34. Show by writing out the explicit meaning of the exponential parts that (3.0 × 10 ) = 9.0 × 10 .
                                                  3 2
                                                                      3
                                                             3
                     Ans.                  (3.0 × 10 ) = (3.0 × 10 )(3.0 × 10 )
                                                    = 3.0 × 3.0 × (10 × 10 × 10) × (10 × 10 × 10)
                                                    = 9.0 × 10 6
               2.35.  Simplify:
                           1              1             10 −4
                     (a)             (b)            (c)
                         10 −3           10 6           10 −4

                                             0
                     Ans.  (a)10 3  (b)10 −6  (c)10 = 1
   34   35   36   37   38   39   40   41   42   43   44