Page 45 - Theory and Problems of BEGINNING CHEMISTRY
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34                        MATHEMATICAL METHODS IN CHEMISTRY                       [CHAP. 2


               TEMPERATURE SCALES
                               ◦
               2.70.  Convert −40 F to degrees Celsius.
                                                          ◦ 5
                                                                        ◦ 5
                                                ◦ C = ( F − 32 ) = (−40 − 32 ) =−40 C
                                                     ◦
                                                                   ◦
                                                                                ◦
                     Ans.                                   9            9
               2.71.  Change the following temperatures in degrees Celsius to kelvins: (a)15 C, (b) −15 C, and (c) −265 C.
                                                                                                     ◦
                                                                              ◦
                                                                                       ◦
                                        ◦
                                  ◦
                     Ans.  (a)  15 C + 273 = 288 K
                           (b)  −15 C + 273 = 258 K
                                   ◦
                                          ◦
                           (c)  −265 C + 273 = 8K
                                           ◦
                                    ◦
               2.72.  Change the following temperatures in kelvins to degrees Celsius: (a) 330 K, (b) 282 K, and (c) 302 K.
                                              ◦
                                      ◦
                               ◦
                     Ans.  (a)57 C(b)9 C(c)29 C
                                            Supplementary Problems
               2.73.  Change 42.30 km/h to meters per second.
                                             42.30 km 1000 m      1h     1 min

                     Ans.                                                   = 11.75 m/s
                                                h     1km     60 min  60 s
               2.74.  Match the value on the first line below with each corresponding value on the second line. (More than one value might
                     correspond for each.)
                     1 µL 1kL 1L    1mL
                                                           0
                                               3
                     1dm 3  1cm 3  1mm 3  1m 3  10 L10 −3  L10 L10 −6  L
                                                            3
                                                                 0
                                     3
                     Ans.  1 µL = 1mm = 10 −6  L   1 L = 1dm = 10 L
                                                             3
                                   3
                                        3
                           1kL = 1m = 10 L         1 mL = 1cm = 10 −3  L
               2.75.  What exponential number best represents each of the following metric prefixes? (a) deci, (b) nano, (c) centi,
                     (d ) micro, (e) milli, and (f ) kilo
                     Ans.  (a)10 −1  (b)10 −9  (c)10 −2  (d)10 −6  (e)10 −3  (f)10 3
               2.76.  A certain beaker has a mass of 141.2 g. When 13.0 mL of an organic liquid is placed in the beaker, the total mass is
                     150.5 g. Calculate the density of the liquid to the proper number of significant digits.
                     Ans.  The mass of the liquid is 150.5g − 141.2g = 9.3g.
                           Its density is (9.3 g)/(13.0 mL) = 0.72 g/mL.

               2.77.  A beaker plus contents has a combined mass of 130.3 g. The beaker has a mass of 129.1 g. If the density of the
                     contents is 2.04 g/mL, what is the volume of the contents to the correct number of significant digits?
                                                                  1mL

                     Ans.                         (130.3g − 129.1g)     = 0.59 mL
                                                                 2.04 g
                           There are only two significant digits since the subtraction yields an answer with two significant digits. That
                           answer limits the final volume to two significant digits.
               2.78.  Make the following English-metric conversions:

                     (a) Change 4.22 in. to cm                 (d) Change 21.7 lb to grams
                     (b) Change 2.35 kg to pounds              (e)  Change 60.0 mi/h to meters per second
                                                                              2
                     (c)  Change 6.13 L to fluid ounces         (f)  Change 3.50 in. to cm 2
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