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DECISION  THEORY                            [CHAP.  8



                  Then by Eqs. (8.1) and (8.2) and using Table A (Appendix A), we obtain















        8.7.   In the binary communication system of  Prob. 8.6, suppose that P(H,) =  and P(H,) = 4.
              (a)  Using the MAP test, determine which signal is transmitted when x = 0.6.
              (b)  Find PI and PI,.
              (a)  Using the result of Prob. 8.6 and Eq. (8.15), the MAP test is given by




                  Taking the natural logarithm of the above expression, we get



                  Since x = 0.6 < 1.193, we determine that signal s,(t)  was transmitted.
              (b)  The decision regions are given by
                                           Ro = {x: x < 1.193) = (-MI,   1.193)
                                           R1 = {x: x > 1.193) = (1.193, a)

                  Thus, by Eqs. (8.1) and (8.2) and using Table A (Appendix A), we obtain













         8.8.   Derive the Neyman-Pearson test, Eq. (8.1 7).

                  From Eq. (8.1 6), the objective function is
                                 J  = (1  - 8) - n(a - a,)  = P(Dl ]HI) - R[P(D,  (H,) - a,,]   (8.29)
              where 1 is an undetermined Lagrange multiplier which is chosen to satisfy the constraint a = a,.  Now, we
              wish to choose the critical region R, to maximize J. Using Eqs. (8.1) and (8.2), we have
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