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CHAP. 6]                        INORGANIC NOMENCLATURE                                101


                     Ans.  In each case, the answer is CaS. Part (b) gives the ions and their changes and so is perhaps easiest to answer.
                           Part (a) gives the elements, so it is necessary to know that periodic group IIA elements always form 2+ ions
                           in all their compounds and that sulfur forms a 2– ion in its compounds with metals. It is also necessary to
                           remember that the metal is named first. In part (c), the fact that there is only one compound of these two
                           elements is reinforced by the fact that the calcium is stated with no Roman numeral, and that sulfide is a
                           specific ion with a specific(2–) charge.

               6.61.  Name (a)Cu 2 O and (b) CuO.
                     Ans.  (a) Copper(I) oxide  (b) Copper(II) oxide.

                                               −
               6.62.  Distinguish between ClO 2 and ClO 2 .
                                                 −
                     Ans.  ClO 2 is a compound, and ClO 2 is an ion—part of a compound.
               6.63.  Use the periodic table relationships to write formulas for (a) the selenate ion and (b) the arsenate ion.
                     Ans.  Selenium is below sulfur in the periodic table, and arsenic is below phosphorus. We write formulas analogous
                                                           2−         3−
                           to those for sulfate and phosphate: (a) SeO 4  and (b) AsO 4 .
               6.64.  Complete the following table by writing the formula of the compound formed by the cation at the left and the anion
                     at the top. NH 4 Cl is given as an example.
                                             Cl −    ClO −   ClO 2 −  SO 3  2−  PO 4  3−

                                       +
                                    NH 4    NH 4 Cl
                                    K +
                                    Ba 2+
                                    Al 3+

                     Ans.                 Cl −     ClO −      ClO 2  −    SO 3 2−    PO 4  3−

                                    +
                                NH 4     NH 4 Cl  NH 4 ClO   NH 4 ClO 2  (NH 4 ) 2 SO 3  (NH 4 ) 3 PO 4
                                K +      KCl      KClO       KClO 2     K 2 SO 3    K 3 PO 4
                                Ba 2+    BaCl 2   Ba(ClO) 2  Ba(ClO 2 ) 2  BaSO 3   Ba 3 (PO 4 ) 2
                                Al 3+    AlCl 3   Al(ClO) 3  Al(ClO 2 ) 3  Al 2 (SO 3 ) 3  AlPO 4
               6.65.  From the data of Table 6-4, determine which charge is most common for first transition series elements (those
                     elements in period 4 among the transition groups).
                     Ans.  The 2+ charge is seen to be most common, occurring with every element in the first transition series that is
                           listed. (Only Sc has no 2+ ion.)

               6.66.  Name the compounds of Problem 6.64.


                     Ans.               Cl −          ClO −        ClO 2  −     SO 3  2−   PO 4 3−
                                 +
                             NH 4     Ammonium    Ammonium       Ammonium     Ammonium    Ammonium
                                       chloride     hypochlorite   chlorite    sulfite       phosphate
                             K +      Potassium   Potassium      Potassium    Potassium   Potassium
                                       chloride     hypochlorite   chlorite    sulfite       phosphate
                             Ba 2+    Barium      Barium         Barium       Barium      Barium
                                       chloride     hypochlorite   chlorite    sulfite       phosphate
                             Al 3+    Aluminum    Aluminum       Aluminum     Aluminum    Aluminum
                                       chloride     hypochlorite   chlorite    sulfite       phosphate
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