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CHAP. 9]                           NET IONIC EQUATIONS                                137


                                                  Solved Problems

               WRITING NET IONIC EQUATIONS
               9.1.  How many types of ions are generally found in any ionic compound?
                      Ans.  Two—one type of cation and one type of anion. (Alums are an exception. They are composed of two different
                           cations and sulfate ions.)
               9.2.  Which of the following compounds are ionic? Which are soluble? Which would be written as separate
                     ions in an ionic equation as written for the first equation in this section? Write the species as they
                     would appear in an ionic equation. (a) CuCl, (b)NH 4 C 2 H 3 O 2 ,(c)Hg 2 Cl 2 ,(d) CoCl 2 ,(e)Na 3 PO 4 , and
                     (f)CH 3 OH(aq).

                                                            Written    Formulas in Ionic
                     Ans.                  Ionic  Soluble  Separately    Equation

                           (a) CuCl        Yes      No        No       CuCl
                                           Yes      Yes       Yes         +        −
                           (b)NH 4 C 2 H 3 O 2                         NH 4 + C 2 H 3 O 2
                                           Yes      No        No
                           (c)Hg 2 Cl 2                                Hg 2 Cl 2
                                           Yes      Yes       Yes      Co + 2Cl −
                                                                         2+
                           (d) CoCl 2
                                           Yes      Yes       Yes         +      3−
                           (e)Na 3 PO 4                                3Na + PO 4
                           (f)CH 3 OH(aq)  No       Yes       No       CH 3 OH
               9.3.  Write the formulas for the ions present in each of the following compounds: (a) NaClO 4 ,(b) BaCl 2 ,(c)
                     KClO, (d) Ba(NO 3 ) 2 ,(e) LiClO 3 ,(f) (NH 4 ) 3 PO 4 ,(g)Co 3 (PO 3 ) 2 ,(h) AgCl(s), and (i) Mg(HCO 3 ) 2 .
                     Ans.  (a)Na and ClO 4 −        (e)  Li and ClO 3  −     (h)Ag and Cl (even though it is
                                                                                          −
                                 +
                                                                                   +
                                                          +
                           (b)Ba 2+  and Cl −       (f )  NH 4 and PO 4  3−      a solid)
                                                           +
                                +
                           (c)  K and ClO −         (g)Co 2+  and PO 3  3−   (i)  Mg 2+  and HCO 3 −
                           (d)Ba 2+  and NO 3  −
               9.4.  Write a net ionic equation for the equation in each of the following parts:
                     (a)NH 4 I + AgClO 3 −→ AgI(s) + NH 4 ClO 3
                     (b)H 2 SO 4 + BaCl 2 −→ BaSO 4 + 2 HCl
                                −
                                     +
                     Ans.  (a)I + Ag −→ AgI    (b)SO 4 2−  + Ba 2+  −→ BaSO 4
               9.5.  Write a net ionic equation for the equation in each of the following parts:
                     (a) HNO 3 + NaHCO 3 −→ NaNO 3 + CO 2 + H 2 O
                     (b) NaOH + NH 4 ClO 3 −→ NH 3 + H 2 O + NaClO 3
                     (c)HC 2 H 3 O 2 + KOH −→ KC 2 H 3 O 2 + H 2 O
                     (d) Ba(OH) 2 (aq) + 2H −→ BaI 2 + 2H 2 O

                                       −
                               +
                     Ans.  (a)H + HCO 3 −→ CO 2 + H 2 O  (HNO 3 is strong)
                                       +
                                 −
                           (b)OH + NH 4 −→ NH 3 + H 2 O
                           (c)HC 2 H 3 O 2 + OH −→ C 2 H 3 O 2 + H 2 O  (HC 2 H 3 O 2 is weak)
                                                     −
                                          −
                           (d)OH + H −→ H 2 O
                                 −
                                     +
               9.6.  Given that BaCO 3 is insoluble in water and that NH 3 and H 2 O are covalent compounds, write net ionic
                     equations for the following processes:
                     (a)NH 4 Cl + NaOH −→ NH 3 + H 2 O + NaCl
                     (b) BaCl 2 + Li 2 CO 3 −→ BaCO 3 + 2 LiCl
                                   +
                                        −
                      Ans.  (a)NH 4 + OH −→ NH 3 + H 2 O  (b)Ba 2+  + CO 3  2−  −→ BaCO 3
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