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CHAP. 13]                       KINETIC MOLECULAR THEORY                              199


                           masses of molecules could be prepared with the naturally occurring mixture. Naturally occurring fluorine
                           exists 100% as  19 F, and molecules of its gaseous compound with uranium, UF 6 , will have two different
                           masses, corresponding to  235 UF 6 and  238 UF 6 . Uranium has been separated into its isotopes by repeated
                           effusion of UF 6 through towers of porous dividers. Each process enriches the individual isotopes a little, and
                           very many repetitions are required to get relatively pure isotopes.

               13.9.  Calculate the ratio of rates of effusion of  238 UF 6 and  235 UF 6 . Fluorine is 100%  19 F.
                     Ans.  The masses of the molecules are 352 and 349 amu. The relative rates of effusion are

                                                              352
                                                                 = 1.004
                                                              349
                           The molecules of  235 UF 6 will travel on average 1.004 times as fast as those of  238 UF 6 .
               13.10. List the different molecular masses possible in UCl 3 with  238 U and  235 U as well as  35 Cl and  37 Cl.
                                                                        35
                                              35
                     Ans.                 238  U( Cl) 3  343 amu    235  U( Cl) 3  340 amu
                                                                        35
                                                                             37
                                                   37
                                          238 U( Cl) 2 ( Cl)  345 amu  235 U( Cl) 2 ( Cl)  342 amu
                                              35
                                          238  35  37    347 amu    235  35  37    344 amu
                                            U( Cl)( Cl) 2             U( Cl)( Cl) 2
                                          238  37        349 amu    235  37        346 amu
                                            U( Cl) 3                  U( Cl) 3
                                                                                            2
                                                                                      1
               13.11. What possible complications would there be in trying to separate hydrogen into H and H by gaseous
                     diffusion?
                                                                                       1
                                                                                        2
                                                                                               2
                                                                                   1
                     Ans.  Hydrogen occurs as diatomic molecules, and it would be easy to separate H 2 , H H, and H 2 , but not
                                                              2
                           the individual atoms. There would be very little H 2 since the heavy isotope accounts for only 0.015% of
                           naturally occurring hydrogen atoms.
                                            Supplementary Problems
                                                   Total volume of gas molecules
               13.12. (a) Is the ratio
                                                      Volume of gas sample
                     smaller for a given sample of gas at constant pressure at 300 K or at 400 K? (b) Will the gas exhibit more ideal
                     behavior at 300 K or at 400 K?
                     Ans.  (a) The ratio is smaller at 400 K. The volume of the molecules themselves does not change appreciably
                               between the two temperatures, but the gas volume changes according to Charles’ law.
                           (b) Since the gas volume is larger at 400 K, the gas molecules are farther apart at that temperature and
                               exhibit lower intermolecular forces. The gas is therefore more ideal at the higher temperature.

                                                   Total volume of gas molecules
               13.13. (a) Is the ratio
                                                      Volume of gas sample
                     smaller for a given sample of gas at constant temperature at 1.00 atm or at 2.00 atm? (b) Will the gas exhibit more
                     ideal behavior at 1.00 atm or at 2.00 atm?
                     Ans.  (a) The ratio is smaller at 1.00 atm. The volume of the molecules themselves does not change appreciably
                               between the two pressures, but the gas volume changes according to Boyle’slaw.
                           (b) Since the gas volume is larger at 1.00 atm, the gas molecules are farther apart at that temperature, and
                               exhibit lower intermolecular forces. The gas is therefore more ideal at the lower pressure.

               13.14. (a) Calculate the average kinetic energy of O 2 molecules at 1.00 atm and 300 K. (b) Does the pressure matter?
                     (c) Does the identity of the gas matter?
                                             3
                     Ans.  (a)          KE = kT = 1.5[1.38 × 10 −23  J/(molecule·K)](300 K) = 6.21 × 10 −21  J
                                             2
                           (b) and (c) The pressure and the identity of the gas do not matter.
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