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CHAP. 19]                           NUCLEAR REACTIONS                                 281


                                          Table 19-1 Products of Natural Radioactivity

                          Symbol      Name       Mass Number   Charge          Identity


                            α      Alpha particle     4          2+      Helium nucleus
                            β      Beta particle      0          1−      High-energy electron
                            γ      Gamma ray          0            0     High-energy particle of light

                                                       Mass number


                                                  4 a        0 b     0 g
                                                  2        −1        0

                                                         Charge
                   The superscripts refer to the mass numbers of the particles; the subscripts refer to their charges.
                   Nuclear equations are written with both the total charge and the total of the mass numbers unchanged from
               reactants to products. That is, the total of the subscripts of the reactants equals the total of the subscripts of the
               products, and the total of the superscripts of the reactants equals the total of the superscripts of the products. The
               subscripts of isotopes may be omitted because the symbol of the element gives the atomic number.


               EXAMPLE 19.1. Show that the mass number and the total charge are both conserved in the natural disintegration of  238 U:
                                                                                                     92
                                                    238     234
                                                      U −→    Th + α
                Ans.  The equation may be rewritten including all atomic numbers and mass numbers:
                                                        4
                                          238 U −→  234 Th + He  or  238  U −→  234 Th + α
                                                                                  4
                                          92      90    2           92     90     2
                     Adding the 234 + 4 superscripts of the products gives the superscript of the reactant. Adding the 90 + 2 subscripts
                     of the products gives the subscript of the reactant. The nuclear equation is balanced.


               EXAMPLE 19.2. Complete the following nuclear equation:
                                                     233    233
                                                       Pa −→  U + ?
                Ans.  Inserting the proper subscript and superscript indicates that the product is a particle with 1− charge and 0 mass
                     number:
                                                      233     233    0 ?
                                                       91  Pa −→  92 U +  −1
                     The missing particle is a beta particle (Table 19-1).
                                                      233     233    0 β
                                                       91  Pa −→  92 U +  −1
                     Note that a beta particle has been emitted from the nucleus. This change has been accompanied by the increase in
                     the number of protons by 1 and a decrease in the number of neutrons by 1. In effect, a neutron has been converted
                     to a proton and an electron, and the electron has been ejected from the nucleus.

                   The emission of a gamma particle causes no change in the charge or mass number of the original particle.
               (It does cause a change in the internal energy of the nucleus, however.) For example,

                                                  119      119     0
                                                                   0
                                                   50 Sn −→  50 Sn + γ
               The same  119 Sn isotope is produced, but it has a lower energy after the emission of the gamma particle.
                        50
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