Page 86 - Separation process engineering
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Example 2-2. Multicomponent flash distillation

                      A flash chamber operating at 50°C and 200 kPa is separating 1000 kmol/h of a feed that is 30 mol%
                      propane, 10 mol% n-butane, 15 mol% n-pentane and 45 mol% n-hexane. Find the product
                      compositions and flow rates.

                      Solution

                      A. Define. We want to calculate y, x, V, and L for the equilibrium flash chamber shown in the
                                                                i
                                                             i
                         diagram.




















                      B. Explore. Since T         and p      are given, a sequential solution can be used. We can use the
                                             drum       drum
                         Rachford-Rice equation to solve for V/F and then find x, y, L, and V.
                                                                                            i
                                                                                         i
                      C. Plan. Calculate K from DePriester charts or from Eq. (2-30). Use Newtonian convergence with
                                              i
                         the Rachford-Rice equation, Eq. (2-46), to converge on the correct V/F value. Once the correct V/F
                         has been found, calculate x from Eq. (2-38) and y from Eq. (2-39). Calculate V from V/F and L
                                                                                  i
                                                        i
                         from overall mass balance, Eq. (2-5).
                      D. Do it. From the DePriester chart (Fig. 2-11), at 50°C and 200 kPa we find








                      Calculate f (V/F) from the Rachford-Rice equation:






                      Pick V/F = 0.1 as first guess (this illustrates convergence for a poor first guess).







                      Since f(0.1) is positive, a higher value for V/F is required. Note that only one term in the denominator
                      of each term changes. Thus we can set up the equation so that only V/F will change. Then f(V/F)
                      equals







                      Now all subsequent calculations will be easier.

                      The derivative of the R-R equation can be calculated for this first guess
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