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Brockenbrough_Ch03.qxd  9/29/05  5:05 PM  Page 3.55



                                                           CONNECTIONS


                                                                                          CONNECTIONS  3.55

                                  Design strength for web buckling with combined force (39 kips applied axially):
                                                     V       33  × 4 50 
                                                                     .
                                                                                    <
                                            φR =   φF −  S   A = 45 −  24 1 .   985  = 382 kips 39 kips  OK
                                                       e
                                                                         .
                                                            
                                              n
                                                   cr
                                  Design tensile strength of bolt for shear/tension interaction:
                                    Design strength is φF nt ′, where F nt ′= 1.3F nt − (F nt /φF nv )f v ≤ F nt
                                                             90    33    
                                                                                      ×
                                                                                  ≤
                                                         ×
                                                     
                                             φ ′ = .075 13 90 −      2      = 64.5 0.75 90  = 67.5 ksi
                                                       .
                                              F
                                               nt
                                                                  (.
                                                                
                                                             36 6 0 75) ( π 4 /) 
                                             φ ′ =F nt  64 5 .   ksi
                                    Design tensile strength of  / 4-in-diameter A325N bolt reduced for shear is
                                                        3
                                                       φr n ′=φF nt ′A b = 64.5 × 0.442 = 28.5 kips/bolt
                                    For 6 bolts = 28.5 × 6 = 171 kips ≥ 39 kips  OK
                                  Design strength for prying action of angles:
                                    Follow procedure in AISC Manual. See Art. 3.5 for background.
                                    a = distance from bolt centerline to edge of angle = 1.93 in
                                    b = distance from bolt centerline to centerline of angle leg = 2.76 in
                                    d b = bolt diameter = 0.75 in
                                    d h = bolt diameter = 0.875 in
                                    p = tributary length per bolt = 2.83 in
                                    d′= width of hole along length of angle = 0.875 in
                                    a′= a + d b /2 ≤ 1.25 × b + d b /2 = 1.93 + 0.75/2 ≤ 1.25 × 2.76 + 0.75/2
                                      = 2.30 ≤ 2.98  Use a′= 2.30 in
                                    b′= b − d b /2 = 2.76 − 0.75/2 = 2.38 in
                                    ρ= b′/a′= 2.38/2.30 = 1.03
                                    δ= 1 − d′/p = 1 − 0.875/2.83 = 0.691
                                    t c = angle thickness required to develop strength of bolt with no prying action, in
                                                        4 44φ Rb′       4 44  × 28 5 2 38
                                                                        .
                                                         .
                                                                              .
                                                                                × .
                                                   t =       n     t =               = 135 in
                                                                                       .
                                                    c
                                                                            .
                                                          pF t      c      283 × 58
                                                         
                                                                                    .
                                              α ′ =  1   t c  2  −  1   α ′ =  1     135   2  −  1   = 261
                                                       
                                                                                               .
                                                         
                                                                       .
                                                                              .
                                                 δ 1 (  + ρ)   t    0 691 1 (  +1 03)    0 625   
                                                                                    .
                                                               2          .    2
                                                              t
                                          α ′ >1; therefore T d  = φr n ′   1 (  + δ)  = 28 5 .   0 625   1 (  + 0 691)  = 10 3 .   kips bolt
                                                                                     .
                                                                                                 /
                                                             
                                                              t
                                                                           135
                                                                             .
                                                              c
                                    For 6 bolts = 10.3 × 6 = 61.8 kips ≥ 39 kips  OK
                      3.4.3 Example: Extended Single-Plate Shear Connections
                                  Single-plate shear connections as shown in Fig. 3.35 can be very economical connections. In-fill
                                  beams can be drilled on the fabricator’s drill line with no further handling, since the beams will
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